Answer:
Explanation:
As we know that tank itself has mass given as 13.4 kg
so it is given as
also the tank contains air in it and the mass of air inside the tank is also given as 4.47 kg
so it is
so total mass of the tank is the mass of the empty tank and mass of air in the tank
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The first ariplanr was made December 17, 1903
Answer:
25.6 V
Explanation:
The kinetic energy of electron associated with its potential difference is given by eV which is equal to the 1/2 mv^2.
m = 9.1 x 10^-31 kg, v = 3 x 10^6 m/s, e = 1.6 x 10^-19 C
eV = 1/2 m v^2
V = mv^2 / 2 e
V = (9.1 x 10^-31) x (3 x 10^6)^2 / (2 x 1.6 x 10^-19)
V = 25.6 V
Answer:
W_net = μ 5.58, μ = 0.1 W_net = 0.558 J
Explanation:
The work is defined by the related
W = F. d = F d cos θ
where bold indicates vectors.
In the case, the work of the friction force on a circular surface is requested.
The expression for the friction force is
fr = μ N
the friction force opposes the movement, therefore the angle is 180º and the cos 180 = -1
W = - fr d
the path traveled half the length of the circle
L = 2 π R
d = L / 2
d = π R
we substitute
W = - μ N d
Total work is initial to
W_neto = - μ π R (N_b - N_a)
let's calculate
W_net = - μ π 0.550 (0.670 - 3.90)
W_net = μ 5.58
for the complete calculation it is necessary to know the friction coefficient, if we assume that μ = 0.1
W_net = 0.1 5.58
W_net = 0.558 J
