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3 years ago

What is the electric potential, i.e. the voltage, 0.30 m from a point charge of 6.4 x 10-C?

Physics

1 answer:

Gwar [14]3 years ago

3 0

Answer:

V = 192 kV

Explanation:

Given that,

Charge, $q=6.4\times 10^{-6}\ C$

Distance, r = 0.3 m

We need to find the electric potential at a distance of 0.3 m from a point charge. The formula for electric potential is given by :

$V=\dfrac{kq}{r}\\\\V=\dfrac{9\times 10^9\times 6.4\times 10^{-6}}{0.3}\\\\V=192000\ V\\\\V=192\ kV$

So, the required electric potential is 192 kV.

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Space pilot Mavis zips past Stanley at a constant speed relative to him of 0.800c. Mavis and Stanley start timers at zero when t

yawa3891 [41]

Answer:

a) $x=2*10^{9} m$ and $t=8.35 s$

b) t = γt', so it is 8.35 s.

Explanation:

a) The equation of Lorentz transformations is given by:

$x=\gamma(x'+ut')$

x' and t' are the position and time in the moving system of reference, and u is the speed of the space ship. x is related to the observer reference.

x' = 0
t' = 5.00 s
u =0.800 c, c is the speed of light 3*10⁸ m/s

$\gamma=\frac{1}{\sqrt{1-(u/c)^{2}}}$

$\gamma=\frac{1}{\sqrt{1-(0.800c/c)^{2}}}$

$\gamma=\frac{1}{\sqrt{1-(0.800)^{2}}}$

$\gamma=1.67$

$x=1.67(0+0.800c*5.00)$

$x=2*10^{9} m$

Now, to find t we apply the same analysis:

$t=\gamma(t'+\frac{ux'}{c^{2}})$

but as x'=0 we just have:

$t=\gamma(t')$

$t=1.67*5.00=8.35 s$

b) Here, Mavis reads 5 s on her watch and Stanley measured the events at a time affected by the Lorentz factor, in other words t = γt', if we see it is the same a) part. So the time interval will be equal to 8.35 s.

I hope it helps you!

5 0

3 years ago

Read 2 more answers

The faintest sound an ear can hear (20 micro-pascals) is roughly ______ times smaller than atmospheric pressure at sea level.

gtnhenbr [62]

Answer: $5.06\times10^{9}$

At sea level, there is one standard atmospheric pressure which is equal to 101.325 kilopascals.

The pressure of faintest sound that a human ear can hear is 20 micro-pascals.

taking the ratio of two:

$\frac {101.325 kilopascals. }{20 micropascals} = \frac {101.325 \times 10^{3}Pa}{20 \times 10^{-6}Pa}$

$=5.06\times10^{9}$

Hence, the atmospheric pressure at sea level is $5.06\times10^{9}$ times greater than the faintest sound that a human ear can hear.

6 0

3 years ago

I NEED HELP ASAP PLEASE!

REY [17]

Answer: thermal conductivity

7 0

3 years ago

Read 2 more answers

(Please help asap)

siniylev [52]

The answer would be B

5 0

3 years ago

The chemical symbol for sulfuric acid is H2SO4. How many atoms are contained in each molecule of sulfuric acid?

cricket20 [7]

You know from looking at the molecular formula that one molecule of H2SO4 contains 2 atoms of hydrogen, 1 atom of sulfur and 4 atoms of oxygen.

5 0

3 years ago