Answer:

Explanation:
Assume the reaction is the combustion of propane.
Word equation: propane plus oxygen produces carbon dioxide and water
Chemical eqn: C₃H₈(g) + O₂(g) ⟶ CO₂(g) + H₂O(g)
Balanced eqn: C₃H₈(g) + 5O₂(g) ⟶ 3CO₂(g) + 4H₂O(g)
(a) Table of enthalpies of formation of reactants and products

(b)Total enthalpies of reactants and products

ΔᵣH° is negative, so the reaction is exothermic.
Answer:
Reaction rate is increased by an increase in kinetic energy
of the reacting particles when their
is _temperature_
increased
A . Collision theory
B . Surface Area
C . Temperature
D. Concentration
229.25 mL of isopropyl alcohol
425.75 mL of water
Explanation:
Knowing that the solution have a 35.0 % (v/v) isopropyl alcohol in water, we can calculate the volume of each component as following.
volume of isopropyl alcohol = (35/100) × solution volume
volume of isopropyl alcohol = 0.35 × 655 mL = 229.25 mL
Now, knowing the volume of isopropyl alcohol we can determine the volume of water.
volume of the solution = volume of isopropyl alcohol + volume of water
volume of water = volume of the solution - volume of isopropyl alcohol
volume of water = 655 mL - 229.25 mL = 425.75 mL
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percent by volume concentration
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Answer:
1045
Answer: 1045 J of energy was released on cooling the down the water from 20 °C to 10 °C.
Answer is (4) - Pb.
According to the reactivity series of elements
- the elements which are above the hydrogen are more reactive than hydrogen.
- the elements which are below the hydrogen are less reactive than hydrogen.
Among the given choices, only Pb is placed above the hydrogen in the reactivity series and rest are below the hydrogen.
Hence, Pb is more active than hydrogen.