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4 years ago

Harry Hess’s explained how oceanic crust is produced and destroyed in his theory of _______

1 answer:

8 0

<span>Harry Hess’s explained how oceanic crust is produced and destroyed in his theory of </span>D. Sea floor spreading

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r-ruslan [8.4K]

Answer:

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3 years ago

15. A substance that has a melting point of 1074 K

inna [77]

Answer:

Ionic solid.

Explanation:

Ionic solid dissociated into free ions capable of conducting electricity in aqueous solution. Ionic solids are also characterised by high melting point due to strong ionic bonds. No free ions or electrons to conduct electricity in solid form.

3 0

3 years ago

At 35.0°C and 3.00 atm pressure, a gas has a volume of 1.40 L. What pressure does the gas have at 0.00°C and a volume of 0.950 L

Luba_88 [7]

The answer to your question is

A. P2=P1V1T2/T1V2

Trust me I am learning this stuff in class and I got everything memorized

I hope this helps

May I have brainliest I am working on my ranks! :)

7 0

3 years ago

Read 2 more answers

What volume of 0.10 M NaOH is required to neutralize 30 mL of 0.10 M HCl?

coldgirl [10]

30 mL. The two compounds need to balance each other out.

5 0

3 years ago

Read 2 more answers

If 2.0×10−4 moles of S2O2−8 in 170 mL of solution is consumed in 170 seconds , what is the rate of consumption of S2O2−8?

Ostrovityanka [42]

Answer : The rate of consumption of $S_2O_2^{-8}$ is, $7.0\times 10^{-6}M/s$

Explanation : Given,

Moles of $S_2O_2^{-8}$ = $2.0\times 10^{-4}mol$

Volume of solution = 170 mL = 0.170 L (1 L = 1000 mL)

Time = 170 s

First we have to calculate the concentration.

$\text{Concentration}=\frac{\text{Moles}}{\text{Volume of solution}}$

$\text{Concentration}=\frac{2.0\times 10^{-4}mol}{0.170L}$

$\text{Concentration}=1.2\times 10^{-3}M$

Now we have to calculate the rate of consumption.

$\text{Rate of consumption}=\frac{\text{Concentration}}{\text{Time}}$

$\text{Rate of consumption}=\frac{1.2\times 10^{-3}M}{170s}$

$\text{Rate of consumption}=7.0\times 10^{-6}M/s$

Thus, the rate of consumption of $S_2O_2^{-8}$ is, $7.0\times 10^{-6}M/s$

8 0

3 years ago