Answer:
5.66g/ml
Explanation:
Mass of Metal Slug, m = 25.17g
Volume of container (flask), v = 59.7ml
Mass of Methanol, M = 43.7g with density, d = 0.791g/ml
Therefore,
Volume of Methanol = M/d = 43.7 / 0.791 = 55.25ml
Volume of Metal slug in the flask = v - V = 59.7 - 55.25 = 4.45ml
Density of Metal slug = mass of metal slug / volume of metal slug
= 25.17 / 4.45 = 5.66g/ml
Answer:
136.36 mL
Explanation:
Here we have to use the dilution formula
From C1V1= C2V2
Where;
C1= initial concentration of the solution= 12.0 M
C2= final concentration of the solution= 2.20 M
V1 = initial volume of the solution= 25.0 ml
V2= final volume of the solution= ?????
Then recall;
C1V1=C2V2
V2 = C1V1/C2
Substituting values from the parameters given;
V2= 12.0 × 25.0 / 2.20
V2= 136.36 mL
Cacl2 dissolve in water according to the following equation
Cacl2 + H2O = Ca(OH) + Hcl
Volume= moles/molarity
The reacting ratio between CaCl2 to Ca(OH) is 1:1
therefore moles of solution is also 0.0262 moles hence volume is =
0.0262mol/ 0.52mol/l = 0.0504L or50.4ml
One mole of Fe(NO3)3, or iron(III) nitrate, has three moles of nitrate molecules, which have three moles of oxygen atoms each. We can show this mathematically:
1 mole Fe(NO3)3 * (3 moles NO3)/(1 mole Fe(NO3)3) = 3 moles NO3
3 moles NO3 * (3 moles Oxygen)/(1 mole NO3) = 9 moles Oxygen
9 moles of Oxygen in one mole Fe(NO3)3
