Answer:
1.57 litres
Explanation:
use pascal's law of volume and temperature
Answer:
- <em>The vapor pressure of the solution at 25°C is </em><u><em>23.6 mmHg</em></u>
Explanation:
<u>1) Data:</u>
- Mass of solute, sucroese, m₁ = 40.0 g
- Mass of solvent, water, m₂ = 250. g
- Vapor pressure of solution, p = ?
- Vapor pressure of pure water, p⁰ = 23.76 mm Hg
<u>2) Principles and formulae:</u>
- Raoult's law states that the vapor pressure of a solution is equal to the mole fraction of the solvent times the vapor pressure of the pure liquid.
p = X p⁰
<u>3) Solution:</u>
a) <u>Mole fraction of the solvent (water)</u>
- X = number of moles of solvent / number of moles of solution
- number of moles of solvent, n₁ = mass in grams / molar mass
n₁ = 250. g / 18.015 g/mol = 13.88 moles
- number of moles of solute, n₂ = mass in grams / molar mass
n₂ = 40.0 g / 342,3 g/mol = 0.12 moles
- total number of moles, n₁ + n₂ = 13.88 moles + 0.12 moles = 14.0 moles
- moles fraction of water, X = 13.88 moles / 14.0 moles = 0.99
b) <u>Vapor pressure of the solution</u>:
- p = p⁰ X = 23.76 mmHg × 0.99 = 23.56 mm Hg
Rounding to three significant figures: 23.6 mm Hg.
Answer:
1. Nucleic acids
2. Proteins carbohydrates
3. Lipids
All of which are essential to the cell’s functions. Each is an Important component of the cell and performs a wide array of functions. Combine, these molecules and it will make up the majority of the cell’s mass.
OR ELSE UR A DEAD RAT HEHE :P
Answer:
780 g
Explanation:
Step 1: Given data
Moles of sodium phosphate: 4.76 moles
Step 2: Calculate the mass corresponding to 4.76 moles of sodium phosphate
To convert moles to mass, we need a conversion factor. In this case, we will use the molar mass of sodium phosphate, which is 163.94 g/mol.
4.76 mol × 163.94 g/mol = 780 g
Answer:
c) Check to see if there's a better medication for the patient's problem.
d) Dispense an extra dose to save the patient from having to return in case of loss or damage to one of the doses.
e ) Compare the label on the medication with the order from the physician .