Answer:
the answer is a) 100*
the angles it is bigger than is an acute angle (below 90)* and a right angle (exactly 90*) so the answer is anything above 90* and so it has to be 100*
For a), this is clearly a given as it is literally to the right of where it says “Given:”
For b), since ON bisects ∠JOH, this means that it splits it into two separate angles - JON and HON, which are similar due to that bisects mean that it splits it equally into two halves
For c), since NO is the same thing as NO, it is equal to itself
For d), since AAS (angle-angle-side) congruence states that if there are two angles that are congruent (proved in a) and b) ) as well as that a side is congruent (proved in c) ), two triangles are congruent
For e), since two triangles are congruent, every side must have one side that it matches up to in the other triangle. As the opposite side of angle H is JO and the opposite side of angle J is OH, and ∠J=∠H, those two are congruent. As JN and HN are the two sides left, they must be congruent.
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Answer:
C. 16 feet.
Step-by-step explanation:
<u>How to find the maximum height of a projectile</u>
if α = 90°, then the formula simplifies to: hmax = h + V₀² / (2 * g) and the time of flight is the longest.
if α = 45°, then the equation may be written as:
if α = 0°, then vertical velocity is equal to 0 (Vy = 0), and that's the case of horizontal projectile motion.
The line that is horizontal on a graph
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Answer:
The x- coordinates are equal at -3.
Step-by-step explanation:
