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viva [34]
3 years ago
12

Juan inflates a balloon and then releases its end to let the balloon go free as air comes out. The balloon then flies around the

room.
Which statement describes how this example is an application of Newton’s laws of motion?

According to Newton’s first law of motion, the balloon continues moving until the forces on it are unbalanced.
According to Newton’s third law of motion, the balloon is pushed forward as the air is forced out.
According to Newton’s third law of motion, the balloon resists any change of motion unless an unbalanced force acts upon it.
According to Newton’s second law of motion, the balloon exerts a force on the air, which exerts a force back on the balloon.
Physics
2 answers:
Ne4ueva [31]3 years ago
4 0

Answer: either the second or fourth statement

Klio2033 [76]3 years ago
4 0

Answer:

its b

Explanation:

According to Newton’s third law of motion, the balloon is pushed forward as the air is forced out.

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a spring with a spring constant of 65 n/m is displaced -94cm. what is the magnitude of the force exerted by the spring
garri49 [273]

Answer:

Explanation:

F = kx = 65 N/m(0.94 m) = 61.1 = 61 N

8 0
3 years ago
At room temperature of 30 degree celsius, a glass of water takes one minute to cool from 80 degree celsius to 60 degree Celsius.
sdas [7]
It will take 30 seconds
6 0
3 years ago
An archer pulls her bowstring back 0.376 m by exerting a force that increases uniformly from zero to 251 N. (a) What is the equi
Amanda [17]

Answer:

(A) 667.5 N/m

(B)

Explanation:

(A) Let the spring constant be k.

Using the formula F = kx

k = 251 / 0.376

K = 667.5 N/m

(B)

Work done

W = 0.5 × kx^2

W = 0.5 × 667.5 × 0.376 × 0.376

W = 47.2 J

8 0
3 years ago
A baseball thrown by a pitcher is hit by a batter. At the moment when the ball hits the bat, the force exerted on the bat by the
Slav-nsk [51]

Newton's Laws of motion describe the motion of an object based on the applied force

The correct option that gives the relationships between the forces is the the option;

\underline{F_{ball}}<u> on bat</u> = \underline{F_{bat}}<u> on ball</u>

<em>(Either option A or B without the minus symbol before </em>F_{bat}<em>, likely typographical error)</em>

<em />

Reason:

Force exerted on the bat by the ball = F_{ball}

Force exerted on the ball by the bat = F_{bat}

Given that the batter hits the ball with the bat, the force exerted by the bat on the ball, F_{bat}, is reacted to by the force of the ball acting on the bat, F_{ball}

According to Newton's third law of motion, action and reaction are equal and opposite. Therefore, at the moment when the ball hits the bat, we have;

\underline{F_{ball}}<u> on bat</u> = \underline{F_{bat}}<u> on ball</u>

<em>Where the force of the bat is high, the ball is accelerated to travel at high speed</em>

Learn more Newton's Laws of motion here:

brainly.com/question/24522313

8 0
3 years ago
Starting from rest, a particle that is confined to move along a straight line is accelerated at a rate of 5.0 m/s2. Which one of
Elanso [62]

Answer:

c) The slope is not constant and increases with increasing time.

Explanation:

The equation for the position of this particle (starting from rest is)

s = at^2/2 = 5t^2/2 = 2.5t^2

We can take derivative of this with respect to time t to get the equation of slope:

s' = (2.5t^2)' = 2*2.5t = 5t

As time t increase, the slope would increases with time as well.

6 0
4 years ago
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