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3 years ago

The forces on a car are balanced.state and explain the resultant force on the car

Physics

1 answer:

Vanyuwa [196]3 years ago

5 0

there will no resultant force

Explanation:

this is because if the forces are balanced on opposite direction. then they cancel each other out

5 newton's ---------> <--------- 5 newton's

then both forces will cancel each other out as a result there is no resultant force and the newton's laws states that if there is no resultant the object will continue in its state of rest (remains there) or it will in continue in its uniform motion in a straight line.

I hope you understand,

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Two red blood cells each have a mass of 9.0 × 10 − 14 kg and carry a negative charge spread uniformly over their surfaces. The r

Gennadij [26K]

Answer:

321.39 m/s

$1.3772213803 \times 10^{10}\ m/s^2$

Explanation:

m = Mass = $9\times 10^{-14}\ kg$

$q_1$ = Charge = -2.50 pC

$q_2$ = Charge = -3.10 pC

r = Radius = 3.75 μm

$\varepsilon_{0}$ = Vacuum permittivity = $8.85 \times 10^{-12}\ F/m$

We have the relation

$m v^{2} &=\frac{q_{1} q_{2}}{4 \pi \varepsilon_{0} 2 r}$

$v =\sqrt{\frac{q_{1} q_{2}}{4 \pi \varepsilon_{0}(2 r)(m)}}$

$=\sqrt{\frac{\left(-2.50 \times 10^{-12}\right)\left(-3.1 \times 10^{-12}\right)}{4(3.14)\left(8.85 \times 10^{-12}\right)\left(2 \times 3.75 \times 10^{-6}\right)\left(9 \times 10^{-14}\right)}}$

$=321.39\ m/s$

The Speed they need when very far away from each other to get close enough to just touch is 321.39 m/s

We have the relation

$m a=\frac{q_{1} q_{2}}{4 \pi \varepsilon_{0}(2 r)^{2}}$

$a=\frac{q_{1} q_{2}}{4 \pi \varepsilon_{0}(2 r)^{2}(m)}$

$=\frac{\left(-2.50 \times 10^{-12}\right)\left(-3.10 \times 10^{-12}\right)}{4(3.14)\left(8.85 \times 10^{-12}\right)\left(2 \times 3.75 \times 10^{-6}\right)^{2}\left(9 \times 10^{-14}\right)}$

$a=1.3772213803 \times 10^{10} \mathrm{m} / \mathrm{s}^{2}$

The acceleration is $1.3772213803 \times 10^{10}\ m/s^2$

8 0

3 years ago

In connective tissue, the role of elastic fibers is to __________.

blagie [28]

The role of elastic fiber is to keep the tissue length(or elasticity). That means if the tissue is stretched the elastic fiber will exert force to make it back into the normal length. This fiber can be found<span> in skin and lack of it will make wrinkle. Other connective tissue would be collagen which will give strength</span>

6 0

3 years ago

A lightweight string is wrapped several times around the rim of a small hoop. If the free end of the string is held in place and

MariettaO [177]

Answer:

Explanation:

Let T be the tension

For linear motion of hoop downwards

mg -T = ma , m is mass of the hoop . a is linear acceleration of CG of hoop .

For rotational motion of hoop

Torque by tension

T x R , R is radius of hoop.

Angular acceleration be α,

Linear acceleration a = α R

So TR = I α

= I a / R

a = TR² / I

Putting this value in earlier relation

mg -T = m TR² / I

mg = T ( 1 + m R² / I )

T = mg / ( 1 + m R² / I )

mg / ( 1 + R² / k² )

Tension is less than mg or weight because denominator of the expression is more than 1.

5 0

3 years ago

A plumber heats a plastic pipe, softens it, shapes it, and then lets it cool. After it is hardened, the

aev [14]

Answer:

thermoset

Explanation:

A thermoset material is a polymer that is irreversibly hardened by curing. Curing is induced by heat and cannot be undone because the polymers cross link during the process, creating permanent chemical bonds.

3 0

3 years ago

A woman exerts a horizontal force of 4 pounds on a box as she pushes it up a ramp that is 10 feet long and inclined at an angle

stealth61 [152]

Answer:

W = 34.64 ft-lbs

Explanation:

given,

Horizontal force = 4 lb

distance of push, d = 10 ft

angle of ramp, θ = 30°

Work done on the box = ?

We know,

W = F.d cos θ

W = 4 x 10 x cos 30°

W = 40 x 0.8660

W = 34.64 ft-lbs

Hence, work done on the box is equal to W = 34.64 ft-lbs

6 0

3 years ago