Given that the block have two applied masses 250 g at East and 100 g at South. In order to make a situation in which block moves towards point A, we have to apply minimum number of masses to the blocks. In order to prevent block moving toward East, we have to apply a mass at West, equal to the magnitude of mass at East but opposite in direction. Therefore, mass of 250 g at West is the required additional mass that has to be added. There is already 100 g of mass acting at South, that will attract block towards South or point A. No need to add further mass in North-South direction.
Answer:
So the minimum force is
32.2Newton
Explanation:
To solve for the minimum force, let us assume it to be F (N)
So
F=mgsinA
But
=>>>> coefficient of static friction x (F + mgcosA
=>3 x 9.8 x sin35 = 0.3 x (F + 3 x 9.8 x cos35)
So making F subject of formula
F + 24.0 = 56.2
F = 32.2N
Answer:
answer is C
Explanation:
acceleration is rate of changing velocity in a time
Answer:
40.1m/s
Explanation:
This is a kinematics problem
x = 82m
a = -9.8m/s^2
v(initial) = 0
Find: v(final)
Using kinematics equation:
vf^2 = vi^2 + 2a(delta)x
vf^2 = 0 + 2*(-9.8)*(82)
vf = sqrt(1607.2) = 40.09m/s
The is traveling with a velocity of 40.1m/s when it hits the ground.
