they're essentially the same thing so i'd say yes
Answer: F. All the above.
Explanation:
Basically, if an object is moving, it moves with a certain velocity and mass. Momentum of a body is a product of mass and velocity. The sum of momentum of individual bodies is equal to the entire system momentum. For instance, a block v is moving due to an applied force F, with a velocity V and the gravity g. Due to gravity, the weight is mg. Due to gravity, the weight is acting downward. Applied force is acting on the block surface area A.
Pressure = Surface force/Surface area.
Surface force is acting on the surface applied. So, acting pressure = Force applied/area.
Pressure and surface force is acting on the body. Body forces also act on the system. Forces due to gravity is also referred to as body force. As a result of weight of the box, Normal force produced by the rough surface is equal to the Weight. As a result of rough surface, frictional forces are produced which opposes the block to move forward. All the external forces create a net total force due to which the block move with a velocity and acceleration.
In Newton's second law, Ftotal is equal to mass × acceleration.
Therefore, we can conclude that momentum can change as a result of all these forces because mass × acceleration is related to total force and momentum is equal to mass × velocity.
Answer:
total_cost = cost + tax
Explanation:
Step1) Let the 2 variable for take input from user e.g price and quantity
var price ;
var quantity ;
var cost ;
var tax ;
var total_cost ;
Step2) take input from user quantity of item 'A'
step3) cost = price * quantity
Step4) tax = 0.08 * cost
Step5) total_cost = cost + tax
Step6) print the total_cost
Answer:
Tech A is correct
Explanation:
Tech A is right as its V- angle is identified by splitting the No by 720 °. Of the piston at the edge of the piston.
Tech B is incorrect, as the V-Angle will be 720/10 = 72 for the V-10 motor, and he says 60 °.
Answer:
L = 46.35 m
Explanation:
GIVEN DATA
\dot m = 0.25 kg/s
D = 40 mm
P_1 = 690 kPa
P_2 = 650 kPa
T_1 = 40° = 313 K
head loss equation
![[\frac{P_1}{\rho} +\alpha \frac{v_1^2}{2} +gz_1] -[\frac{P_2}{\rho} +\alpha \frac{v_2^2}{2} +gz_2] = h_l +h_m](https://tex.z-dn.net/?f=%5B%5Cfrac%7BP_1%7D%7B%5Crho%7D%20%2B%5Calpha%20%5Cfrac%7Bv_1%5E2%7D%7B2%7D%20%2Bgz_1%5D%20-%5B%5Cfrac%7BP_2%7D%7B%5Crho%7D%20%2B%5Calpha%20%5Cfrac%7Bv_2%5E2%7D%7B2%7D%20%2Bgz_2%5D%20%3D%20h_l%20%2Bh_m)
where
density is constant
head is same so,
curvature is constant so
neglecting minor losses
we know
is given as
therefore
V = 25.90 m/s
for T = 40 Degree, 
Re = 4.16*10^5 > 2300 therefore turbulent flow
for Re =4.16*10^5 , f = 0.0134
Therefore
L = 46.35 m
