Answer:
0.85 mol/L.
Explanation:
- Molarity is defined as the no. of moles of solute dissolved in a liter of the solution.
<em>M = (no. of moles of solute)/(Volume of the solution (L))</em>
no. of moles of calcium phosphate = 2.125 mol.
Volume of the solution = 2.5 L.
<em>∴ M of calcium phosphate</em> = (2.125 mol)/(2.5 L) = <em>0.85 mol/L.</em>
Answer:
Three
Explanation:
Three hydrogen bonds are between guanine and cytosine base pairs
Hopefully, that helps!
The empirical formula is K₂O.
The empirical formula is the <em>simplest whole-number ratio</em> of atoms in a compound.
The <em>ratio of atom</em>s is the same as the <em>ratio of moles</em>.
So, our job is to calculate the <em>molar ratio</em> of K to O.
Step 1. Calculate the <em>moles of each element
</em>
Moles of K = 32.1 g K × (1 mol K/(39.10 g K =) = 0.8210 mol K
Moles of O = 6.57 g O × (1 mol O/16.00 g O) = 0.4106 mol 0
Step 2. Calculate the <em>molar ratio of each elemen</em>t
Divide each number by the smallest number of moles and round off to an integer
K:O = 0.8210:0.4106 = 1.999:1 ≈ 2:1
Step 3: Write the <em>empirical formula
</em>
EF = K₂O
Answer:
-152.92°C
Explanation:
Initial volume = 0.750 mL
Initial temperature = -32.7 °C (-32.7 + 273.15 K = 240.45 k)
Final temperature = ?
Final volume = 0.750 mL / 2= 0.375 mL
Solution:
The given problem will be solve through the Charles Law.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
T₂ = T₁V₂ / V₁
T₂ = 240.45 k × 0.375 mL / 0.750 mL
T₂ = 90.17 mL.K / 0.750 mL
T₂ = 120.23 K
Temperature in celsius:
120.23 K - 273.15 = -152.92°C