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GrogVix [38]
3 years ago
11

Why do different substances have diffrent properties

Physics
2 answers:
Artist 52 [7]3 years ago
8 0
Different elements require different levels of energy to make or break a bond
user100 [1]3 years ago
8 0
Different elements require different levels of energy to make or break a bond
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a 1 gram spiders sits on a platform rotating at 78 rpm. the spider is 15 cm from the centre disk. find the speed of the spider
olga nikolaevna [1]

The spider is traveling in a circle with radius = 15cm

The circumference of any circle = <em>2 pi (radius)</em>
The circumference of the spider's path = 2 pi (15 cm) = 30 pi cm

The spider completes a trip around this path 78 times per minute.
Its speed, relative to you, is   

                               (78) x (30 pi) cm/min =

                                       2,340 pi cm/min =  7,351.33 cm/min =

                                     <em>  73.5133 meter/min =</em>

                                       <em>4.411 km/hr =</em>

                                         <em>2.74  miles/hour

</em>
(After the last appearance of pi,
all numbers are rounded.)<em>

</em>
8 0
3 years ago
PLEASE HELP.<br>i am begging for someone to help me with this physics lab. ​
ANEK [815]

Answer:

whats the question... you didn't put the question up

6 0
3 years ago
What is the freezing point of an aqueous solution that boils at 101 degrees C? Kfp = 1.86 K/m and Kbp = 0.512 K/m. Enter your an
astra-53 [7]

Answer:

-3.63 degree Celsius

Explanation:

We are given that

Boiling point of solution=T_b=101^{\circ} C

Boiling point water=100 degree Celsius

K_f=1.86K/m

K_b=0.512 K/m

\Delta T_b=T-T_0

Where T=Boiling point of solution

T_0=Boiling point of pure solvent

\Delta T_b=101-100=1^{\circ}C

\Delta T_b=k_bm

Using the formula

1=0.512\times m

Molality,m=\frac{1}{0.512} m

\Delta T_f=k_fm

Using the formula

\Delta T_f=\frac{1}{0.512}\times 1.86

\Delta T_f=3.63 C

We know that

\Delta T_f=T_0-T_1

Where T_0 =Freezing point of solvent

T_1= Freezing point of solution

Using the formula

3.63=0-T_1

Freezing point of water=0 degree Celsius

T_1=0-3.63=-3.63 C

Hence, the freezing point of solution=-3.63 degree Celsius

7 0
3 years ago
How much time will it take a car travelling at 88 km/hr (55mi/hr) to travel 500 km
Illusion [34]
5.6 hours to go 500km
7 0
3 years ago
(a) Two identical open boxes originally contain the same volume of water. One is kept at 15°C and the other at 85°C for the same
Tresset [83]

Explanation:

because as you can see beaker 2 has higher temperature. As volume is directly propotional

to temperature. So the the water molecules has

more energy so that's why levels are different.

6 0
2 years ago
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