Answer:
The answer to your question is 178.6 g
Explanation:
Data
ΔT = 1.8 °C
mass = 17.5 g
mass of water = 100 g
Kc = 1.86
Process
1.- Calculate the molality using the following formula
ΔTc = mKc
solve for m
m = ΔTc/Kc
substitution
m = 1.8/1.86
result
m = 0.968
2.- Calculate the number of moles
m = # of moles/kg of solvent
kg of solvent = 0.1 kg
# of moles = m x kg of solvent
# of moles = 0.968 x 0.1
# of moles = 0.0968
3.- Calculate the molar mass
x g molar mass --------------------- 1 mol
17.5 g --------------------- 0.0968 moles
x = (1 x 17.5)/0.0968
x = 178.6 g
Answer:
The answer to your question is No
Explanation:
Ionic bonding is a kind of bonding that involves the attraction between oppositely charged ions. That means that one element must have a positive charge and the other a negative charge.
Also, the difference in electronegativity of both elements must be higher than 1.7.
Both Sodium and Aluminum are positively charged then an ionic bond is not possible to be formed.
Difference of electronegativity = 1.61 (Al) - 0.93(Na)
= 0.63
To form an ionic bond the difference of electronegativity must be higher than 1.7.
Answer:
0.42mole
Explanation:
Given parameters:
Number of atoms of titanium = 2.5 x 10²³atoms
Unknown:
Number of moles = ?
Solution:
To solve this problem, we must understand that a mole of any substance contains the Avogadro's number of particles.
6.02 x 10²³ atoms makes up 1 mole of an atom
2.5 x 10²³ atoms will contain 
= 0.42mole
Answer : The thermal energy produced during the complete combustion of one mole of cymene is -7193 kJ/mole
Explanation :
First we have to calculate the heat released by the combustion.
where,
q = heat released = ?
= specific heat of calorimeter = 
= change in temperature = 
Now put all the given values in the above formula, we get:
Thus, the heat released by the combustion = 70.43 kJ
Now we have to calculate the molar enthalpy combustion.
where,
= molar enthalpy combustion = ?
q = heat released = 70.43 kJ
n = number of moles cymene = 
Therefore, the thermal energy produced during the complete combustion of one mole of cymene is -7193 kJ/mole
(On my left) (On my right side)
Na: 1. Na:1
Cl:2. Cl:1
Na:1 x 2 =2
Na:1 x 2=2
Cl: 1 x 2 = 2
Answer:
2Na + Cl2 -> 2NaCl
