What is the percent composition of Sb2F3.What is the percent composition of F in this molecule? Round the answer to five signifi
1 answer:
Answer:
Explanation:
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In this case, a percent composition is computed by considering the atomic mass of each element in the compound as well as the number of atoms and the molar mass of the compound. Thus, Sb2F3 has a molar mass of 300.52 g/mol, antimony has an atomic mass of 121.76 g/mol and fluorine 19.0 g/mol, therefore, the percent composition of fluorine which has three atoms with five significant figures is:
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Answer:
According to the following position vs. Time graph the bicyclist was : D
D. Not moving for the first two seconds, then begin moving at the constant speed.
Explanation:
Along Y-axis = Distance in meters
Along X-axis = Time taken in second
- For first 2 seconds the The object has not changed its position.There is Zero distance covered.So , Speed = 0
- After 2 second,The Object changed the distance by equal amount in equal interval of time.(Uniform Speed).Hence at each point after 2 second, there is same value speed
<u>Answer:</u>
<u>For a:</u> The standard Gibbs free energy of the reaction is -347.4 kJ
<u>For b:</u> The standard Gibbs free energy of the reaction is 746.91 kJ
<u>Explanation:</u>
Relationship between standard Gibbs free energy and standard electrode potential follows:
............(1)
- <u>For a:</u>
The given chemical equation follows:
<u>Oxidation half reaction:</u> ( × 2)
<u>Reduction half reaction:</u>
We are given:
Putting values in equation 1, we get:
Hence, the standard Gibbs free energy of the reaction is -347.4 kJ
- <u>For b:</u>
The given chemical equation follows:
<u>Oxidation half reaction:</u> ( × 6)
<u>Reduction half reaction:</u>
We are given:
Putting values in equation 1, we get:
Hence, the standard Gibbs free energy of the reaction is 746.91 kJ
Answer:
see explaination
Explanation:
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