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Rus_ich [418]
3 years ago
14

How can an object enter Earth's orbit?​

Chemistry
1 answer:
pentagon [3]3 years ago
3 0
When an object enters the Earth's atmosphere, it experiences a few forces, including gravity and drag. Gravity will naturally pull an object back to earth.



-Hope this helped, have a great day. ;)
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When hydrogens on an unsaturated fatty acid lie on the same side of the carbon-carbon double bond, a ____________ formation exis
dedylja [7]
When hydrogen ................................... a CIS formation exist.
There are two types of formation which are possible in fatty acids, these are CIS and TRANS configurations.
A fat is described as a CIS fatty acid if its hydrogen atoms are lying on the same side of the carbon carbon double bonds. A fat is said to be a trans fatty acid, if the hydrogen atoms in its molecules are lying on the opposite sides of the carbon bonds.
7 0
3 years ago
6.285×10^3 mg = _____? _____ kg
TiliK225 [7]
One kilogram is equal to one thousand grams. Further, one gram is equal to 1000 mg. The conversion is as shown below,
                    (6.285 x 10³ mg) x (1 g / 1000 mg) x (1 kg / 1000 g)
The numerical value of the operation above is 0.006285 kg. 
6 0
4 years ago
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If someone adds million of small fish to a lake, how would the number of big fish change
Molodets [167]
The population of big fish would increase because they have more food
6 0
3 years ago
What makes an atom a good conductor?
andrew-mc [135]
Very little electric force is required to cause electron flow in conductors. This is due to electrons called "free electrons", which exist in the atoms of conductors. "Free electrons" are electrons that are very weakly bonded to the atom. ... Metals such as copper, silver, and gold are good conductors.

Well, atoms are loosely bound and free to move through the material. Almost all, or just most, atoms will hold on to electrons very tightly and are insulators.
3 0
3 years ago
How many ml of a 0.50m solution of hno3 solution are needed to make 500 ml of 0.15m hno3
Anna71 [15]

Answer:

150.0 mL.

Explanation:

  • It is known that the no. of millimoles of HNO₃ before dilution = the no. of millimoles of HNO₃ after dilution.

∵ (MV) before dilution = (MV) after dilution.

<em>∴ V before dilution = (MV) after dilution / M before dilution</em> = (0.15 M)(500.0 mL)/(0.50 M) = <em>150.0 mL.</em>

7 0
3 years ago
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