Answer:
The answer is 0.5 Hz
Explanation:
Its pretty easy to get the answer. One hertz (Hz) is equal to one cycle or period per second. So, just divide the period by the number of seconds.
1 period/2 secs = 1/2 Hz or 0.5 Hz
Given data:
* The mass of the ball is 2 kg.
* The gravitational field strength at the surface of planet X is 5 N/kg.
Solution:
The weight of the ball on the planet X is,

where m is the mass of ball, a is the gravitational field strength,
Substituting the known values,

Thus, the weight of the ball on the surface of planet X is 10 N.
To begin with, we can use the formula that links frequency, wavelength and velocity.
Because you already have the wavelength and the frequency, you just need to solve for velocity. You can do this by multiplying each side of the equation by frequency.
Therefore, 400 x 2.5 = 1000m/s.
Hope this helps :)
Answer:
The value of gauge pressure at outlet = -38557.224 pascal
Explanation:
Apply Bernoulli' s Equation
+
+
=
+
+
--------------(1)
Where
= Gauge pressure at inlet = 3.70105 pascal
= velocity at inlet = 2.4 
= Gauge pressure at outlet = we have to calculate
= velocity at outlet = 3.5 
= 3.6 m
Put all the values in equation (1) we get,
⇒
+
=
+
+ 3.6
⇒ 0.294 =
+ 0.6244 + 3.6
⇒
= 0.294 - 0.6244 - 3.6
⇒
= - 3.9304
⇒
= - 38557.224 pascal
This is the value of gauge pressure at outlet.