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Darya [45]
3 years ago
8

A boat floats in water a. Archimedes b. Bernoulli c. Density d. Pascal e. Pressure

Physics
2 answers:
Ivenika [448]3 years ago
7 0
The answer is Density !, Do you also need an example ?

Rate this the brainliest answer , Thank youuu !
liubo4ka [24]3 years ago
4 0
Hey there,

Your question states: <span>A boat floats in water  . . . 

Your correct answer would be "density" basically because the density of the water would make the boat float.

Hope this helps you!

~Jurgen</span>
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salantis [7]
400m in 32sec: (400/32)>12.5meters per second>
(12.5)(60)(60)(1/1000)=45km per hour
Constant speed would mean that the two forces are equivalent
7 0
3 years ago
You are running to catch a train which is stationary on the tracks. The whistle is blowing, in preparation for the train’s depar
AlladinOne [14]

Answer:

You would hear a loud trumpet sound that can be heard from a large distance.

Explanation:

7 0
2 years ago
A 10.0 Ω lightbulb is connected to a 12.0 V battery. (a) What current flows through the bulb? (b) What is the power of the bulb?
andreev551 [17]

The current flowing through the bulb as well the power of the bulb are 1.2A and 14.4 Watts respectively.

<h3>What current flows through the bulb as well as the power of the bulb?</h3>

From ohm's law; V = I × R

Where V is the voltage, I is the current and R is the resistance.

Also, Power is expressed as; P = V × I

Where V is voltage and I is current.

Given that;

  • Resistance R = 10.0 ohms
  • Voltage V = 12.0V
  • Current I = ?
  • Power P = ?

First, we determine the current flow through the bulb.

V = I × R

12.0V = I × 10.0 ohms

I = 12.0 ÷ 10.0

I = 1.2A

Next, we determine the power of the bulb.

P = V × I

P = 12.0V × 1.2A

P = 14.4 Watts

Therefore, the current flowing through the bulb as well the power of the bulb are 1.2A and 14.4 Watts respectively.

Learn more about Ohm's law here: brainly.com/question/12948166

#SPJ1

6 0
2 years ago
Three forces act on an object. Two of the forces are at an angle of to each other and have magnitudes N and N. The third is perp
grin007 [14]

Explanation:

Assuming that all forces extend from the origin point, with F_1 and F_2 lying in the xy plane, so F_3 is along the z axis. So, we have:

\vec{F_1}=F_1\hat{i}+0\hat{j}+0\hat{k}\\\vec{F_2}=F_2cos\theta\hat{i}+F_2sin\theta\hat{j}+0\hat{k}\\\vec{F_3}=0\hat{i}+0\hat{j}+F_3\hat{k}

The net force is:

\vec{F}=\vec{F_1}+\vec{F_2}+\vec{F_3}\\\vec{F}=(F_1+F_2cos\theta)\hat{i}+F_2sin\theta\hat{j}+F_3\hat{k}

The force (F_4) that would exactly counterbalance these three forces will be opposite in direction and equal in magnitude to the net force:

\vec{F_4}=-(F_1+F_2cos\theta)\hat{i}-F_2sin\theta\hat{j}-F_3\hat{k}\\F_4=\sqrt{(-(F_1+F_2cos\theta))^2+(-F_2sin\theta)^2+(-F_3)^2}

6 0
3 years ago
The weight of a boy having a mass of 50 kg is_____ N
Elden [556K]

Answer: 490

Explanation:

5 0
3 years ago
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