Answer:
1. q.
2. 2q.
3. 3q.
4. 6q.
Explanation:
We'll begin by calculating the specific heat capacity of the liquid. This can be obtained as follow:
Mass (m) = 25 g
Change in temperature (ΔT) = 20 °C
Heat (Q) = q
Specific heat capacity (C) =?
Q = MCΔT
q = 25 × C × 20
q = 500C
Divide both side by 500
C = q/500
C = 2×10¯³ qg°C
Therefore, the specific heat capacity of liquid is 2×10¯³ qg°C
Now, we shall determine the heat required to produce the various change in temperature as follow:
2. Mass (m) = 50 g
Change in temperature (ΔT) = 20 °C
Specific heat capacity (C) = 2×10¯³ qg°C
Heat (Q) =?
Q = MCΔT
Q = 50 × 2×10¯³ × 20
Q = 2q.
Therefore, the heat required is 2q.
3. Mass (m) = 25 g
Change in temperature (ΔT) = 60 °C
Specific heat capacity (C) = 2×10¯³ qg°C
Heat (Q) =?
Q = MCΔT
Q = 25 × 2×10¯³ × 60
Q = 3q.
Therefore, the heat required is 3q.
4. Mass (m) = 50 g
Change in temperature (ΔT) = 60 °C
Specific heat capacity (C) = 2×10¯³ qg°C
Heat (Q) =?
Q = MCΔT
Q = 50 × 2×10¯³ × 60
Q = 6q.
Therefore, the heat required is 6q.
is the pressure of the gas,
is the volume of the gas,
is the number of moles of particles in this gas,
is the ideal gas constant, and
is the absolute temperature of the gas (in degrees Kelvins.)
;
;
.