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ikadub [295]
3 years ago
9

A box has dimensions: l = 10.0 cm; w = 5.0 cm; h = 2.5 cm determined by a mm ruler. Calculate

Chemistry
1 answer:
olga55 [171]3 years ago
7 0

Answer:

Volume of box =  125 cm³

Explanation:

Given:

Length l = 10 cm

Width b = 5 cm

Height h = 2.5 cm

Find:

Volume of box

Computation:

Volume of box = lbh

Volume of box = 10 x 5 x 2.5

Volume of box =  125 cm³

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In which of the following cases will the LEAST time be required to arrive at equilibrium? K below refers to the equilibrium cons
mylen [45]

Answer: Option (4) is the correct answer.

Explanation:

It is known that equilibrium constant is represented as follows for any general reaction.

                 A + B \rightarrow C + D

                   K = \frac{[C][D]}{[A][B]}

As equilibrium constant is directly proportional to the concentration of products so more is the value of equilibrium constant more will be the number of products formed.

As a result, more is the time taken by the reaction to reach towards equilibrium. Whereas smaller is the value of equilibrium constant more rapidly it will reach towards the equilibrium.

Thus, we can conclude that cases where K is a very small number will require the LEAST time to arrive at equilibrium.

8 0
3 years ago
Which of the following is the balanced equation for the
NNADVOKAT [17]
A.) is the answer =)
6 0
3 years ago
Hydrogen iodide decomposes slowly to H2 and I2 at 600 K. The reaction is second order in HI, and the rate constant is 9.7×10−6M−
Lady bird [3.3K]

Answer : The molarity after a reaction time of 5.00 days is, 0.109 M

Explanation :

The integrated rate law equation for second order reaction follows:

k=\frac{1}{t}\left (\frac{1}{[A]}-\frac{1}{[A]_o}\right)

where,

k = rate constant = 9.7\times 10^{-6}M^{-1}s^{-1}

t = time taken  = 5.00 days

[A] = concentration of substance after time 't' = ?

[A]_o = Initial concentration = 0.110 M

Now put all the given values in above equation, we get:

9.7\times 10^{-6}=\frac{1}{5.00}\left (\frac{1}{[A]}-\frac{1}{(0.110)}\right)

[A]=0.109M

Hence, the molarity after a reaction time of 5.00 days is, 0.109 M

8 0
3 years ago
1. (04.01 LC)
charle [14.2K]

Answer:

I think is Probably B

4 0
2 years ago
Read 2 more answers
A generic weak acid with formula HA has a Ka = 2.76 x 10-8. Calculate the Kb for the conjugate base of the acid.
Reika [66]

Answer:

3.62x10⁻⁷ = Kb

Explanation:

The acid equilibrium of a weak acid, HX, is:

HX + H₂O ⇄ X⁻ + H₃O⁺

Where Ka = [X⁻] [H₃O⁺] / [HX]

And basic equilibrium of the conjugate base, is:

X⁻ + H₂O ⇄ OH⁻ + HX

Where Kb = [OH⁻] [HX] / [X⁻]

To convert Ka to Kb we must use water equilibrium:

2H₂O ⇄ H₃O⁺ + OH⁻

Where Kw = 1x10⁻¹⁴ = [OH⁻] [H₃O⁺]

Thus, we can obtain:

Kw = Ka*Kb

Solving for Kb:

Kw / Ka = Kb

1x10⁻¹⁴ /  2.76x10⁻⁸ =

3.62x10⁻⁷ = Kb

4 0
3 years ago
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