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Rom4ik [11]
2 years ago
13

.....................!!.!...!.!.!!.

Physics
1 answer:
Sindrei [870]2 years ago
4 0

Answer:

6.5 is correct

Explanation:

Have a nice day!

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An electron in a mercury atom jumps from level a to level g by absorbing a single
statuscvo [17]

Answer:

7.39ev

Explanation:

Energy levels are found inside the atom. Electrons occupy these energy levels depending on the energy they possess. Electrons can move from one energy level to another due to absorption or emission of a photon or other factors. As the electron, jumps from a higher energy level to a lower energy level emitting a photon of measurable frequency, the photon carries energy equal to the amount of energy between the gap of the levels. This idea was first proposed by Neils Bohr and became the forerunner of the wave mechanical model of the atom.

Hence the energy of a photon is the energy of the gap between the two energy levels. Since Ea= 2.48ev and Eg= 10.38 ev.

If an electron jumps from Ea to Eg, the energy of the photon absorbed is given by;

E=Eg-Ea

E= 10.38ev - 2.48ev

E= 7.39ev

3 0
3 years ago
An electromagnetic wave moves through electric and magnetic fields. How might the movement of the wave be described?
Elenna [48]

A. The vibrations of the fields are perpendicular to the direction in which the wave moves.

7 0
3 years ago
A person with a remote mountain cabin plans to install her own hydroelectric plant. A nearby stream is 3.00 m wide and 0.500 m d
Lubov Fominskaja [6]

Answer:

The power she can generate is 185.22 KW.

Explanation:

<h3><u>DATA</u></h3>

3.00m wide and 0.500m deep.

Cross sectional area = 1.500m^2

Velocity = 1.35m/s

Volumetric flow rate = Av = 18.00m^3/s

Mass flow rate = 18,000kg/s

Height = 4.20m

25.0% efficiency

<h3><u> FORMULA:</u></h3>

P = dE / dt * eff

<h3><u>SOLUTION:</u></h3>

18,000kg/s (9.8m/s^2) (4.20m) (25%) = 185,220 watts

= 185 kw

6 0
3 years ago
Can you help me doing an essay about actual self​
Rudik [331]

Answer:

yes absolutely

Explanation:

why not

4 0
2 years ago
A rectangular copper strip 1.5cm wide and 0.10cn thick carries a current of 5.0A. Find the Hall voltage for a 1.2T magnetic fiel
Scrat [10]

Answer:

4.4345× 10^-7V

Explanation:

The computation of the half voltage for a 1.2T magnetic field applied is shown below

The volume of one mole of copper is

v = m ÷p

= 63.5 ÷ 8.92

= 7.12cm

Now the density of free electrons in copper is

n = Na ÷ V

= 6.02 × 10^23 ÷ 7.12

= 8.456× 10^28/m^3

Now the half voltage is

= IB ÷ nqt

= (5 × 1.20) ÷ (8.456× 10^28 × 1.6 × 10^-19 × 0.1× 10^-2)

= 4.4345× 10^-7V

7 0
2 years ago
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