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Hunter-Best [27]
3 years ago
6

Gallium (III) carbonate formula

Chemistry
1 answer:
Alex17521 [72]3 years ago
4 0
Ga2(CO3)3 is the formula.
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A solution contains 1.817 mg of CoSO4 (155.0 grams/mole) per mL. Calculate the volume (in mL) of 0.009795 M Zn2 needed to titrat
Nana76 [90]

Answer:

<u> </u><u>85.952 ml</u> Zn^2^+  needed to titrate the excess complexing reagent .

Explanation:

Lets calculate

After addition of 80 ml of EDTA the solution becomes = 20 + 70 = 90 ml

As the number of moles of CoSO_4 =\frac{Given mass }{molar mass}

                                                       =\frac{1.817}{155}

                                                          =0.01172

Molarity = \frac{no. of moles}{volume of solution}

           =\frac{0.01172}{20}

        =0.000586 moles

Excess of EDTA = concentration of EDTA - concentration of CoSO4

                            = 0.009005 - 0.000586

                           = 0.008419 M

As M1V1 ( Excess of EDTA ) = M2V2 (Zn^2^+)

           0.008419\times100ml=0.009795\times V2

           V2=\frac{0.008419\times100}{0.009795}

             V2 =85.952 ml

Therefore , <u>85.952 ml </u>Zn^2^+ needed to titrate the excess complexing reagent .

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How many element does this element have calcium?
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Can you please reword that? I don't understand the question. But I can help you though, I am good at science.
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