What is the difference between digital instruments and decimal scaled instruments to measure

1 answer:

8 0

Answer Digital measuring instruments are self-contained devices that automatically present the value of the measured quantity on a digital display. And Decimal Scaled Instruments: Record all digits that you can certainly determine from the scale markings and estimate one more digit. I hope this Helped I´m new to this.

Explanation:

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To reduce the global emission of greenhouse gases, which of the following would be theMOST effective and practical lifestyle cha

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C. Decrease your consumption of beef.

Explanation:

The production of beef needs lots of land, which leads to trees being cut down, releasing carbon dioxide. Also, the ruminant animals used to produce beef end up farting a lot from their diets, and these farts are of high metane, which leads to greenhouse gases being emitted in the athmosphere.

Common plant proteins, otherwise, produce way less of these gases.

So the correct answer is:

C. Decrease your consumption of beef.

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SRSS is a method used in responce spectram analysis

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Modal analysis is performed to identify the modes, and the response in that mode can be picked from the response spectrum. These peak responses are then combined to estimate a total response. A typical combination method is the square root of the sum of the squares (SRSS) if the modal frequencies are not close.

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A 2-mm-diameter electrical wire is insulated by a 2-mm-thick rubberized sheath (k = 0.13 W/m K), and the wire/sheath interface i

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Answer:

maximum allowable electrical power=4.51W/m

critical radius of the insulation=13mm

Explanation:

Hello!

To solve this heat transfer problem we must initially draw the wire and interpret the whole problem (see attached image)

Subsequently, consider the heat transfer equation from the internal part of the tube to the external air, taking into account the resistance by convection, and conduction as shown in the attached image

to find the critical insulation radius we must divide the conductivity of the material by the external convective coefficient

$r=\frac{k}{h} =\frac{0.13}{10}=0.013m=13mm$