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Oduvanchick [21]
3 years ago
6

A 4 kg billiard ball moving on a horizontal surface has a speed of 16 m/s when it strikes a horizontal coiled spring is brought

to rest in a distance of 0.75 m. What is the spring constant of the spring?
Physics
2 answers:
Yuki888 [10]3 years ago
7 0

Answer:

1820.44 N/m

Explanation:

mass of ball, m = 4 kg

velocity of ball, v = 16 m/s

distance x = 0.75 m

let k be the spring constant.

By the use of conservation of energy,

the kinetic energy of the ball is equal to the potential energy of the spring

\frac{1}{2}mv^{2}=\frac{1}{2}kx^{2}

4 x 16 x 16 = K x 0.75 x 0.75

K = 1820.44 N/m

Thus, the spring constant is 1820.44 N/m.

ruslelena [56]3 years ago
6 0

Answer:

spring constant of the spring is 1820.44 N/m

Explanation:

given data

ball mass = 4 kg

speed = 16 m/s

distance = 0.75 m

to find out

spring constant of the spring

solution

we know that kinetic energy of ball = energy store in spring as compression

so we can express it as

0.5 × m × v² = 0.5 × k × x²    ....................1

so put here value we get spring constant k

m × v² =  k × x²

4 × 16² =  k × 0.75²

solve it we get

k  =  1820.44 N/m

so spring constant of the spring is 1820.44 N/m

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Answer:

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Explanation:

Take counterclockwise to be positive and clockwise to be negative.

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∑τ = 7.5 Nm − 9.8 Nm

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The net torque is 2.3 Nm clockwise.

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Spaceship 1 and Spaceship 2 have equal masses of 300kg. They collide. Spaceship 1's final speed is 3 m/s, and Spaceship 2's fina
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Answer:

B. 1500 kg*m/s

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Momentum p = m* v

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The total momentum before and the total momentum after the collision is the same. We know the mass and speed after the collision so we can calculate the total momentum.

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Substitute the given numbers:

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The only graph that accurately depict the given motion is graph D.

The given parameters;

  • initial position of the man = 0
  • direction of the man's first displacement = backward
  • time of first motion, t₁ = 6 seconds
  • velocity of this first displacement = v₁
  • time without any motion (<em>zero movement</em>) = 6 seconds
  • direction of the second displacement = forward
  • velocity of second displacement = 2v₁

Let the acceleration of the first displacement = a

Acceleration of the second displacement = 2a

From the given graphs we can eliminate every graph without initial decrease or motion towards the negative direction.

The only options with initial motion towards the negative direction are;

  • <em>graph B</em>, and
  • <em>graph D</em>.

The difference between graph B and D;

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  • in graph D there is no motion for 6 seconds (<em>this is obvious as the line fall directly on top of the horizontal axis maintaining a value of zero for 6 seconds</em>).

Thus, the only graph that accurately depict the given motion is graph D.

Learn more here: brainly.com/question/21095906

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