Which statement(s) is/are indicative of a covalent bond?

1 answer:

4 0

Do you have any answer options?

The most I can help is to tell you that a covalent bond is a type of bond that shares electrons between the bonded atoms.

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A ball is projected at an angle of elevation of 60 ° with an initial velocity of 120m/s.calculate

Mrac [35]

Explanation:

It is given that,

The angle of projection is 60 degrees

Initial velocity of the ball is 120 m/s

We need to find the time taken to get to the maximum height and the time of flight.

Time taken to reach the maximum height is given by :

$T=\dfrac{u^2\sin^2\theta}{2g}$

g is acceleration due to gravity

$T=\dfrac{(120)^2\times \sin^2(60)}{2\times 10}\\\\T=540\ s$

(ii) Time of flight,

$t=\dfrac{2u\sin\theta}{g}$

So,

$t=\dfrac{2\times 120\times \sin(60)}{10}\\\\t=20.78\ s$

Hence, this is the required solution.

3 0

3 years ago

A car of mass M = 1000 kg traveling at 50.0 km/hour enters a banked turn covered with ice. The road is banked at an angle θ , an

kupik [55]

The radius of the curved road at the given condition is 54.1 m.

The given parameters:

mass of the car, m = 1000 kg
speed of the car, v = 50 km/h = 13.89 m/s
banking angle, θ = 20⁰

The normal force on the car due to banking curve is calculated as follows;

$Fcos(\theta) = mg$

The horizontal force on the car due to the banking curve is calculated as follows;

$Fsin(\theta) = \frac{mv^2}{r}$

Divide the second equation by the first;

$\frac{Fsin(\theta)}{Fcos(\theta) } = \frac{mv^2}{rmg} \\\\tan(\theta) = \frac{v^2}{rg} \\\\r = \frac{v^2}{g \times tan(\theta)} \\\\r = \frac{13.89^2}{9.8 \times tan(20)} \\\\r = 54.1 \ m$