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kvv77 [185]
2 years ago
13

How many grams of Chromium can be formed when 150 grams of

Chemistry
1 answer:
valentinak56 [21]2 years ago
6 0

Answer: 104 g

Explanation: reaction Cr2O3 + 3 H2 ⇒ 2 Cr + 3 H2O

M(Cr2O3) = 150 g/mol, so n = m/M = 1.0 mol

Number of moles of H2 should be 3.0 moles and

It is much greater (150 g / 2.016 g/mol)

1 mol Cr2O3 produces 2 mol Cr.

Mass m= 2.0 mol· 52g/mol= 104 g

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Answer : The final temperature of the mixture is 29.6^oC

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of iron = 0.499J/g^oC

c_2 = specific heat of water = 4.18J/g^oC

m_1 = mass of iron = 39.9 g

m_2 = mass of water  = Density\times Volume=1g/mL\times 50.0mL=50.0g

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T_1 = initial temperature of iron = 78.1^oC

T_2 = initial temperature of water = 25.0^oC

Now put all the given values in the above formula, we get

(39.9g)\times (0.499J/g^oC)\times (T_f-78.1)^oC=-(50.0g)\times 4.18J/g^oC\times (T_f-25.0)^oC

T_f=29.6^oC

Therefore, the final temperature of the mixture is 29.6^oC

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3 years ago
What is the total anion concentration (in mEq/L ) of a solution that contains 6.0 mEq/L Na + , 11.0 mEq/L Ca 2+ , and 1.0 mEq/L
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