Answer:
I'll be your friend!
Explanation:
If you need help with anything just ask!
Answer:
31.2K
Explanation:
The following data were obtained from the question:
n = 1.42 mol
V = 3L
P = 123 kPa = 123000Pa
Recall: 101325Pa = 1atm
123000Pa = 123000/101325 = 1.21atm
R = 0.082atm.L/Kmol
T =?
Using the ideal gas equation PV = nRT, we can obtain the temperature as follows:
PV = nRT
T = PV/nR
T = (1.21 x 3)/(1.42 x 0.082)
T = 31.2K
Answer:
Freezing and boiling point
Explanation:
A liquid form of any substance is an intermediate form between the solid form and the gaseous form.
Decreasing the temperature of liquid water according to the phase diagram of 
would freeze it and we would have a phase change from liquid to solid (ice) at the freezing point of water.
Similarly, heating water to its boiling point would evaporate water and we would have a phase change from liquid to gas (water vapor).
Therefore, liquid water exists between its freezing and boiling point.
Answer:
4, 16,
Explanation:
SI2 is sulphur diiodide. Sulphur is in group sixteen (six valence electrons) while iodine is in group 17(seven valence electrons).
Since there are two iodine atoms and one sulphur atom, the molecule has twenty valence electrons. Out of these twenty valence electrons, only four are bonding electrons. The other sixteen electrons include the four nonbonding electrons found on sulphur and the twelve non bonding electrons found on the two iodine atoms having six nonbonding electrons each.
