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sertanlavr [38]
3 years ago
15

Please help me with number 4 and 5 please

Chemistry
1 answer:
Stels [109]3 years ago
6 0
4. Is true and 5. Should be volume but I’m not to sure in that one
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Lithium (Li) and oxygen (O) are both in period 2. They both have? a.similar properties
xeze [42]
They both have two electron shells. Period indicates number of shells.
4 0
3 years ago
Read 2 more answers
51.7ml at 27 Celsius and 90kpa to stp
never [62]
STP is the abbreviation of standard condition for temperature and pressure which is 273.15K temperature and 1.013× 10^5 Pa pressure. Since the pressure and temperature changes, I assume the question would ask about the result of the volume. The temperature used in ideal gas should be Kelvin, so 27 Celcius would be 300.15K.
The calculation would be
PV=T
V=T/P

V2/V1= T2*P1/T1*P2
V2/V1=273.15K*  90^10^3Pa/ 300.15K *  1.013× 10^5 Pa
V2= 0.81904 * 51.7ml
V2= 42.34ml
6 0
3 years ago
We make a basic solution by mixing 50. mL of 0.10 M NaOH and 50. mL of 0.10 M Ca(OH)2. It requires 250 mL of an HCl solution to
andreyandreev [35.5K]

<u>Answer:</u> The correct answer is Option 5.

<u>Explanation:</u>

  • To calculate the molarity of the solution after mixing 2 solutions, we use the equation:

M=\frac{n_1M_1V_1+n_2M_2V_2}{V_1+V_2}

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of the NaOH.

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of the Ca(OH)_2

We are given:

n_1=1\\M_1=0.10M\\V_1=50mL\\n_2=2\\M_2=0.1\\V_2=50mL  

Putting all the values in above equation, we get:

M=\frac{(1\times 0.1\times 50)+(2\times 0.1\times 50)}{50+50}\\\\M=0.15M

  • To calculate the molarity of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base.

We are given:

n_1=1\\M_1=?M\\V_1=250mL\\n_2=1\\M_2=0.15M\\V_2=100mL

Putting values in above equation, we get:

1\times M_1\times 250=1\times 0.15\times 100\\\\M_1=0.06M

Hence, the correct answer is Option 5.

7 0
3 years ago
A sample of oxygen occupies 47.2 liters under a pressure of 1240 torr at 298K. What volume would it occupy at 303K if the pressu
kupik [55]

Answer:

81.5 L

Explanation:

We can use the combined gas law equation that gives the relationship among pressure, temperature and volume of gases for a fixed amount of gas.

P1V1 / T1 = P2V2 / T2

where P1 - pressure, V1 - volume and T1 - temperature at the first instance

P2 - pressure, V2 - volume and T2 - temperature at the second instance

substituting the values in the equation

1240 Torr x 47.2 L / 298 K = 730 Torr x V2 / 303 K

V2 = 81.5 L

the new volume the gas would occupy when the conditions have changed is 81.5 L

3 0
3 years ago
Which term represents an intermolecular force in a sample of water?
Sergeu [11.5K]

Answer:

hydrogen bonding

Explanation:

5 0
3 years ago
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