Answer:
Step-by-step explanation:
Since each trial is independent of the other
no of mistakes he does is binomial with p = 1/3
a) the probability that he makes no mistakes on his first 10 orders but the 11th order is a mistake
= 
b) Prob that shanker quits = P(Shankar does I one mistake and Fran does not do the first one)+Prob (Shanker does mistake in the II one while Fran does both right)
= 
Multipy 3 by 6 multiply 1 by 4 and 7 by 4 then add the numbers
<h2>
Forming Equations from Word Problems</h2>
To form equations from word problems, we can derive mathematical operations as well as variables from the given information.
In this case, each time Walker reads a certain number of pages, we subtract that from the total number of pages left to know how many pages is left to read.
<h2>Solving the Question</h2>
<em>Let r represent the pages left to read.</em>
<em />
792 pages in total
Walker reads 15 pages a day during the week and 25 pages a day during the weekend.
- There are 5 weekdays, and he reads 15 pages each of those days. ⇒ <em>r</em> = 792 - 5×15
- There are 2 weekend days, and he reads 25 pages each of those days.
⇒ <em>r</em> = 792 - (5×15 + 2×25)
5 weeks have passed
- Multiply the terms representing the number of pages he reads a week by 5, for 5 weeks.
⇒ <em>r</em> = 792 - (5×15 + 2×25)×5
<h2>Answer</h2>
<em>r</em> = 792 - (5×15 + 2×25)×5
Answer:
C.
Step-by-step explanation:
you have to use the equation 4pir^2. After simplifying, it comes out to 81pi cm^2
