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dalvyx [7]
3 years ago
3

Complete these sentences to identify the types of interference. The type of interference that increases the energy of the result

ing wave is called interference. The type of interference that results in a loss of energy is called interference.
Physics
2 answers:
rusak2 [61]3 years ago
7 0

Answer:

its constructive and destructive

Explanation:

i got it right

yKpoI14uk [10]3 years ago
6 0

Answer:

the result is an increase in energy, this is the so-called CONSTRUCTIVE INTERFERENCE.

resulting energy is zero, this is the so-called DESTRUCTIVE INTERFERENCE

Explanation:

When we have an interference process the optical paths of the two rays are added, when the incident rays arrive in phase the result is an increase in energy, this is the so-called CONSTRUCTIVE INTERFERENCE.

When the rays arrive out of phase a half wavelength the resulting energy is zero, this is the so-called DESTRUCTIVE INTERFERENCE

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Where is the most energy transferred in a food web?
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A steel cable with Cross Sectional Area 3.00cm² has an elastic limit of 2.40 x 10^8pascals. Find the maximum upward acceleration
bazaltina [42]

Answer:

Stress = F / A       force per unit area

A = 3.00 cm^2 = 3 E-4  m^2

F = 2.4E8 N/m^2 * 3E-4 m^2 = 7.2E4 N    max force applied

F/3 = 2.4E4 N  if force not to exceed limit   (= f)

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3 0
3 years ago
Question 3 (1 point)
ASHA 777 [7]

Answer:

twice as much work

Explanation:

7 0
3 years ago
A series RLC circuit is driven by a 1.0-kHz oscillator. The circuit parameters are Vms = 12 V, L = 5.0 mH, C= 4.0 uF, and R=102.
alexgriva [62]

Answer:

C) 12.3 volts

Explanation:

f = frequency of oscillator = 1 kHz = 1000 Hz

V_{rms} = 12 Volts

L = Inductance of Inductor = 5 mH = 0.005 H

X_{L} = Inductive reactance

Inductive reactance is given as

X_{L} = 2\pi fL

X_{L} = 2(3.14) (1000)(0.005)

X_{L} = 31.4

X_{C} = Capacitive reactance

Capacitive reactance is given as

X_{C}=\frac{1}{2\pi fC}

X_{C}=\frac{1}{2(3.14)(1000)(4\times 10^{-6})}

X_{C} = 39.8

Impedance of the circuit is given as

z = \sqrt{R^{2}+(X_{L} - X_{C})^{2}}

z = \sqrt{102^{2}+(31.4 - 39.8)^{2}}

z = 102.35

Rms Current flowing is given as

i = \frac{V_{rms}}{z}

i = \frac{12}{102.35}

i = 0.12 A

Rms potential difference across the resistor is given as

V = i R

V = (0.12) (102)

V = 12.3 volts

5 0
3 years ago
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