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1 year ago

!!!!100 POINTS!!!!

1 answer:

6 0

The event that had the greatest impact in astronomical history during this time period was the launch of Apollo 16.

The research of astronomy during the time period of 1970 - 1990 are given below as;

Date Event

1. 15 June 1974 Black Brant VC sounding rocket from White Sands.

2. 14 May 1973 Launch of Skylab, the USA's first space station

3. 26 July 1971 Launch of Apollo 15

<h3>What is Astronomy?</h3>

Astronomy is a branch of science that deals with celestial bodies and their relationship with each other.

From the information given about astronomy, between the time period 1970 - 1990 as it was on the 26th of December, 1974 that the Soviet space station Salyut-4 was launched.

The event that had the greatest impact in astronomical history during this time period was the launch of Apollo 16.

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Which of these statement describes a chemical property

dimaraw [331]

Explanation:
If there is no no pictures how I will describe???????????

4 0

2 years ago

Determine the mass of a boat that is propelled forward by a force of 1250N at an acceleration of 3 m/s2.

Pavlova-9 [17]

Answer:

416.6 KG

Explanation:

Due to the mass being missing from the equation you divide the force by the acceleration

6 0

2 years ago

If a total force exerted by water in a container with a bottom area of 3 square meters is 900 newtons, what's the water pressure

anyanavicka [17]

<h3>Answer:</h3>

p=300 Pa

<h3>Explanation:</h3>

_______________

S=3 m²

F=900 N

_______________

p - ?

_______________

p=F/S=900 N / 3 m² = 300 Pa

6 0

1 year ago

2. An object with moment of inertia ????1 = 9.7 x 10−4 kg ∙ m2 rotates at a speed of 3.0 rev/s. A 20 g mass with moment of inert

svetoff [14.1K]

Answer:

2.85 rad/s

Explanation:

5 cm = 0.05 m

20 g = 0.02 kg

When dropping the 2nd object at a distance of 0.05 m from the center of mass, its corrected moments of inertia is:

$I_2 = 1.32\times10^{−6} + 0.02 * 0.05^2 = 0.513\times10^{-4} kgm^2$

So the total moment of inertia of the system of 2 objects after the drop is:

$I = I_1 + I_2 = 9.7\times10^{-4} + 0.513\times10^{-4} = 0.0010213 kgm^2$

From here we can apply the law of angular momentum conservation to calculate the post angular speed

$\omega_1 I_1 = \omega_2 I$

$\omega_2 = \omega_1 \frac{I_1}{I} = 3 \frac{9.7\times10^{-4}}{0.0010213} = 2.85 rad/s$

6 0

2 years ago

Determine in symbols an expression for the magnetic force exerted on the falling bar (and determine the direction of that force)

Katarina [22]

Answer:

magnetic force on falling Bar F = B*i*L*sin(90) = B*(B*L*v/R)*L = B^2*L^2*v/R

direction of the force is vertically upwards

Explanation:

8 0

3 years ago