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3 years ago

15 points please help :")

Mathematics

2 answers:

vlabodo [156]3 years ago

8 0

15 is the answer .......

Liono4ka [1.6K]3 years ago

4 0

Answer:

15*C

Step-by-step explanation:

The temperature rises by 2.4 every 3 cycles per second. So you would have to keep the pattern going.

6 cycles p/second = 19.8*C

3 cycles p/second = 17.4*C

0 cycles p/second = 15.0*C

So, because 0 cycles means the engine is resting, 15*C would be the answer.

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A company that produces ribbon has found that the marginal cost of producing x yards of fancy ribbon is given by Upper C prime l

denis-greek [22]

Answer:

Step-by-step explanation:

Given:

$C_{(x)}=-0.00001x^{2}-0.02x+49$

for x≤1400; N = 5

So, Δx = $\frac{1400-0}{5} =280\\\\\int\limits^{1400}_0 {C(x)} \, dx$ =∑C(a + nΔx).Δx

=C(0)Δx + C(280)Δx + C(560)Δx + C(840)Δx + C(1120)Δx

= Δx[C(0) + C(280) + C(560) + C(840) + C(1120)]

= 280[49 + 42.616 + 34.664 + 25.144 + 14.056]

=280[165.48]

=46334 approx

8 0

3 years ago

Parallel / Perpendicular Practice

deff fn [24]

The slope and intercept form is the form of the straight line equation that includes the value of the slope of the line

Neither
║
Neither
⊥
║
Neither
Neither
Neither

Reason:

The slope and intercept form is the form y = m·x + c

Where;

m = The slope

Two equations are parallel if their slopes are equal

Two equations are perpendicular if the relationship between their slopes, m₁, and m₂ are; $m_1 = -\dfrac{1}{m_2}$

1. The given equations are in the slope and intercept form

$\ y = 3 \cdot x + 1$

The slope, m₁ = 3

$y = \dfrac{1}{3} \cdot x + 1$

The slope, m₂ = $\dfrac{1}{3}$

Therefore, the equations are neither parallel or perpendicular

Neither

2. y = 5·x - 3

10·x - 2·y = 7

The second equation can be rewritten in the slope and intercept form as follows;

$y = 5 \cdot x -\dfrac{7}{2}$

Therefore, the two equations are parallel

3. The given equations are;

-2·x - 4·y = -8

-2·x + 4·y = -8

The given equations in slope and intercept form are;

$y = 2 -\dfrac{1}{2} \cdot x$

Slope, m₁ = $-\dfrac{1}{2}$

$y = \dfrac{1}{2} \cdot x - 2$

Slope, m₂ = $\dfrac{1}{2}$

The slopes

Therefore, m₁ ≠ m₂

$m_1 \neq -\dfrac{1}{m_2}$

The lines are Neither parallel nor perpendicular

Neither

4. The given equations are;

2·y - x = 2

$y = \dfrac{1}{2} \cdot x +1$

m₁ = $\dfrac{1}{2}$

y = -2·x + 4

m₂ = -2

Therefore;

$m_1 \neq -\dfrac{1}{m_2}$

Therefore, the lines are perpendicular

5. The given equations are;

4·y = 3·x + 12

-3·x + 4·y = 2

Which gives;

First equation, $y = \dfrac{3}{4} \cdot x + 3$

Second equation, $y = \dfrac{3}{4} \cdot x + \dfrac{1}{2}$

Therefore, m₁ = m₂, the lines are parallel

6. The given equations are;

8·x - 4·y = 16

Which gives; y = 2·x - 4

5·y - 10 = 3, therefore, y = $\dfrac{13}{5}$

Therefore, the two equations are neither parallel nor perpendicular

Neither

7. The equations are;

2·x + 6·y = -3

Which gives $y = -\dfrac{1}{3} \cdot x - \dfrac{1}{2}$

12·y = 4·x + 20

Which gives

$y = \dfrac{1}{3} \cdot x + \dfrac{5}{3}$

m₁ ≠ m₂

$m_1 \neq -\dfrac{1}{m_2}$

Neither

8. 2·x - 5·y = -3

Which gives; $y = \dfrac{2}{5} \cdot x +\dfrac{3}{5}$

5·x + 27 = 6

$x = -\dfrac{21}{5}$

Therefore, the slopes are not equal, or perpendicular, the correct option is Neither

Learn more here:

brainly.com/question/16732089

6 0

3 years ago

The absolute value function, f(x) = –|x| – 3, is shown.

Elanso [62]

Answer: D. all real numbers less than or equal to –3

5 0

3 years ago

∠ A and ∠B are vertical angles. Find each angle if, m∠ A=7x+2 and m∠ B=4x+11. Solve for x

tino4ka555 [31]

Answer:

x=3

Step-by-step explanation:

Vertical angles are equal so

<A = <B

7x+2 = 4x+11

Subtract 4x from each side

7x+2-4x = 4x+11-4x

3x+2 =11

Subtract 2 from each side

3x+2-2 = 11-2

3x = 9

Divide by 3

3x/3 = 9/3

x=3

7 0

3 years ago

Elena’s bus runs every 20 minutes. If she arrives at her bus stop at a random time, what is the probability that she will have t

Bond [772]

We try to represent the data in segments from 0 to 20.
The length of the line segment along the number line from 0 to 5 is 5 - 0 = 5 units. The length of the line segment along the number line from 20 to 5 is 20 - 5 = 15 units. If you were to randomly throw a dart on this number line, then the probability of landing in the shaded region is 15/20 = 3/4 or 75%

6 0

3 years ago

Read 2 more answers