Answer:
Using Hilbert Transformation, we can transmit two independent base-band information signals by using SSB on a common-carrier frequency.
Explanation:
- In SSB modulators, we pre-process a real signal by Hilbert Transform filter to form another real signal
- The signal has the same spectral amplitude but has 90° phase shift at each frequency relative to its input signal.
- The ordered pair gets almost all of its negative components cancelled
- thus, with the use of Hilbert Transformation, we can transmit two independent base-band information signals by using SSB on a common carrier frequency.
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Answer:
a) the flow under full capacity is q₂= 1.334 ft³/s
b) the velocity would be v= 3.793 ft/s
Explanation:
a) Since the pipe has 8 inches in diameter but 4 are covered with water flow ( half of a circle in area=A₁) , q₁=0.662 ft³/s then
q₁=A₁*v
then for the same velocity v but area A₂=2*A₁
flow under full capacity= q₂ = A₂*v= 2*A₁*v= 2*q₁=2*0.662 ft³/s= 1.334 ft³/s
b) when flowing at a depth of 4 inches
A₁= (1/2)*(π*D²/4) = π* (1/8)*(8 in)² = 8π in² * (1 ft²/ 144 in²) = π/18 ft² = 0.1745 ft²
then
v=q₁/A₁ = 0.662 ft³/s/0.1745 ft²= 3.793 ft/s
v= 3.793 ft/s
Answer:
The most likely cause of a double precipitin ring in a RID test is when there is an antigen-antibody reaction ratio within the equivalence zone. The precipitin line forms when the antigen (with one or more epitopes) and antibody are in optimal proportions to each other and form an insoluble precipitates.
The design speed was used for the freeway exit ramp is 11 mph.
<h3>Design speed used in the exit ramp</h3>
The design speed used in the exit ramp is calculated as follows;
f = v²/15R - 0.01e
where;
v = ωr
v = (θ/t) r
θ = 90⁰ = 1.57 rad
v = (1.57 x 19.4)/2.5 s
v = 12.18 ft/s = 8.3 mph
<h3>Design speed</h3>
f = v²/15R - 0.01e
let the maximum superelevation, e = 1%
f = (8.3)²/(15 x 19.4) - 0.01
f = 0.22
0.22 is less than value of f which is 0.4
<h3>next iteration, try 10 mph</h3>
f = (10)²/(15 x 19.4) - 0.01
f = 0.33
0.33 is less than 0.4
<h3>next iteration, try 11 mph</h3>
f = (11)²/(15 x 19.4) - 0.01
f = 0.4
Thus, the design speed was used for the freeway exit ramp is 11 mph.
Learn more about design speed here: brainly.com/question/22279858
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