False it never decreases, it increases or remain the same.
Answer:
The options are:
Test 1: Mix a teaspoon of sodium bicarbonate into a cup of warm water to see if it dissolves.
Test 2: Mix a teaspoon of sodium bicarbonate into a cup of vinegar to see if it fizzes.
Test 3: Heat a teaspoon of sodium bicarbonate in the oven to see if its melting point is less than 400 degrees Fahrenheit.
Which statement provides the best assessment of his tests?
The answer is Test 2: Mix a teaspoon of sodium bicarbonate into a cup of vinegar to see if it fizzes.
This is because it will indicate the chemical property of the sodium bicarbonate as a result of its reaction with another chemical compound, a vinegar.
Tests 1 and 3 will show a physical property of the substance as a result of the physical characteristics such as solubility and melting point .
Note that the methods applied in solving this question is the appropriate method. Check the parameters you gave in the question if you did not expect a complex number for the charges. Thanks
Answer:

Explanation:
Note: When a conducting wire was connected between the spheres, the same charge will flow through the two spheres.
The two charges were 0.65 m apart. i.e. d = 0.65 m
Force, F = 0.030 N
The force or repulsion between the two charges can be calculated using the formula:

Due to the wire connected between the two spheres, 
The sum of the charges on the two spheres = 
Note: When the conducting wire is removed, the two spheres will no longer contain similar charges but will rather share the total charge unequally
Let charge in the first sphere = 
Charge in the second sphere, q₂ = 
Force, F = 0.075 N


Solution :
Acceleration due to gravity of the earth, g 

Acceleration due to gravity at 1000 km depths is :




= 8.23 m/s
Acceleration due to gravity at 2000 km depths is :




= 6.73 m/s
Acceleration due to gravity at 3000 km depths is :



= 5.18 m/s
Acceleration due to gravity at 4000 km depths is :




= 3.64 m/s
Answer:
2y
Explanation:
Electric field in terms of Electric potential is given as:
E = dV/dr(x, y, z)
Where r(x, y, z) = position in x, y, z plane
The y component of the Electric field will be:
Ey = -dV/dy
Given that
V = 2x - y² - cos(z)
dV/dy = -2y
=> E = - (-2y)
E = 2y