Two different bromide solutions are mixed with each other: Solution 1 is an aqueous solution of 4.85 g aluminum bromidein 150. m
1 answer:
Answer:
M=0.380 M.
Explanation:
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In this case, given those two solutions of aluminum bromide and zinc bromide, it is firstly necessary to compute the moles of bromide ions in each solution as shown below:
Now, we compute the total moles of bromide:
Then, the total volume in liters:
Therefore, the concentration of total bromide is:
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Answer:
Explanation:
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In this case, we can first compute the heat required for such temperature increase, considering the molar heat capacity of water (75.38 J/mol°C):
Afterwards, the mass of ice that can be melted is computed by:
So we solve for moles with the proper units handling:
Finally, with the molar mass of water we compute the mass:
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Answer:
The correct answer is 333.8 J
Explanation:
Ice (water in solid state) melts at 273 K (0ºC). During the phase change from solid to liquid, water absorbs 6.01 KJ per mol until it melts completely. To calculate the heat absorbed, we first have to convert the mass of water (1 g) to mol by using the molecular weight of water (H₂O):
Molecular weight of water= 2 x molar mass H + 1 x molar mass O
Molecular weight of water= 2 x 1 g/mol + 16 g/mol= 18 g/mol
mol ice= = 0.055 mol
heat= 0.055 mol x 6.01 KJ/mol= 0.3338 KJ
Finally, we convert KJ to J (1 KJ= 1000 J so we multiply by 1000):
0.3338 KJ x 1000 J/1 KJ= 333.8 J