1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nonamiya [84]
3 years ago
9

Two different bromide solutions are mixed with each other: Solution 1 is an aqueous solution of 4.85 g aluminum bromidein 150. m

l water and solution 2 has a volume of 175 ml and contains 7.75 g of zinc bromide. You mix the two solutions together in a large beaker. What is the bromide concentration in moles/L in the mixture
Chemistry
1 answer:
erma4kov [3.2K]3 years ago
8 0

Answer:

M=0.380 M.

Explanation:

Hello there!

In this case, given those two solutions of aluminum bromide and zinc bromide, it is firstly necessary to compute the moles of bromide ions in each solution as shown below:

n_{Br^-}^{in\ AlBr_3}=4.85 gAlBr_3*\frac{1molAlBr_3}{266.69gAlBr_3}*\frac{3molBr^-}{1molAlBr_3}  =0.05456molBr^-\\\\n_{Br^-}^{in\ ZnBr_2}=7.75gZnBr_2*\frac{1molZnBr_2}{225.22gZnBr_2}*\frac{2molBr^-}{1molZnBr_2}  =0.06882molBr^-

Now, we compute the total moles of bromide:

n_{Br^-}=0.05456mol+0.06882mol\\\\n_{Br^-}=0.12338mol

Then, the total volume in liters:

150mL+175mL=325mL*\frac{1L}{1000mL} \\\\=0.325L

Therefore, the concentration of total bromide is:

M=\frac{0.12338mol}{0.325L}\\\\M=0.380M

Best regards!

You might be interested in
Lets go fishing:).........
kenny6666 [7]

Answer: sure, why not...

Explanation:

3 0
3 years ago
Read 2 more answers
If the symbol X represents a central atom, Y represents outer atoms, and Z represents lone pairs on the central atom, the struct
Inessa05 [86]

Answer:

The correct option is: bent 109°

Explanation:

Covalent molecules are the molecules in which the atoms are linked by covalent bonds. The electrons involved in the formation of a covalent bond are known as shared pair or <u>bond pair of electrons</u>.

The three-dimensional arrangement of the atoms of a molecule in space is known its molecular structure or geometry.

<u>Given molecule</u>: XY₂, having two lone pairs around the central atom X.

Since the molecule XY₂ has <u>two lone pairs</u> and <u>two bond pairs</u> of electrons. Therefore according to the VSEPR theory, the given molecule has a <u>bent molecular geometry with 109° bond angle.</u>

7 0
4 years ago
Which statement gives a disadvantage of multicellular organisms?
dexar [7]

Answer: B. They reproduce slower than unicellular organisms

Explanation:

In unicellular organisms there is a single cell which performs all the functions like digestion, respiration, and reproduction. The cell reproduce by cell division. The single parent cell divides into two identical daughter cells. But multicellular organisms exhibit multiple cells and their reproduction is complex. They reproduce by sexual mode of reproduction in which separate sex cells are produced when they fuse form zygote which is the precursor of new organism. This process is slower than that of the cell division and production of progeny by the unicellular organisms. Thus reproduction is slower in multicellular organism this is the disadvantage in multicellular organisms.

6 0
3 years ago
Read 2 more answers
N2(g) + 2H(g) -&gt; N2 H4(g) What are the volumes of N2 gas and H2 gas required to form 28.5 grams of N2 H4 at 30'C and 1.50 atm
FromTheMoon [43]

Answer:

Volume of N₂ = 14.76 L

Volume of H₂ = 29.52 L

Explanation:

Given data:

Mass of N₂H₄ formed = 28.5 g

Pressure = 1.50 atm

Temperature = 30°C (30+273 = 303 k)

Volume of N₂ and H₂ needed = ?

Solution:

Chemical equation:

N₂ + 2H₂  →  N₂H₄

Number of moles of N₂H₄ formed = mass/ molar mass

Number of moles of N₂H₄ formed = 28.5 g/ 32 g/mol

Number of moles of N₂H₄ formed = 0.89 mol

Now we will compare the moles of N₂H₄ with N₂ and H₂ form balance chemical equation.

                N₂H₄                :                 N₂

                   1                     :                   1

                  0.89               :               0.89

                N₂H₄                :                 H₂

                   1                    :                  2

                 0.89               :                2×0.89 = 1.78 mol

Volume of H₂:

PV = nRT

1.50 atm × V = 1.78 mol × 0.0821 atm.L/mol.K × 303 K

V = 44.28atm.L /1.50 atm

V = 29.52 L

Volume of N₂:

PV = nRT

1.50 atm × V = 0.89 mol × 0.0821 atm.L/mol.K × 303 K

V = 22.14 atm.L /1.50 atm

V = 14.76 L

6 0
3 years ago
Which is a spectator ion in the reaction between these two solutions babr2 + na2so4?
Greeley [361]
Spectator  ion  are  ions  which   remain  unchanged  during  chemical  equation and  does  not  affect  equilibrium
chemical  equation  for  the  reaction  is as follows
  NaSO4   +Babr2  ---> 2  Nabr  +  BaSO4
ionic  equation   is  as  follows
Ba ^+2  +  SO^-2  --->BaSO4(s)
therefore  the spectator  ion  are Na+  and   Br-  ions
6 0
4 years ago
Read 2 more answers
Other questions:
  • Which is larger , an atom or a molecule
    14·2 answers
  • Examine the system of equations.<br> y = 4x +8,<br> y = 4x-1
    10·1 answer
  • A piece of black onyx was cut into a rectangular solid measuring 5.10 cm by 5.10 cm by 2.50 mm . What is the volume in cubic cen
    11·1 answer
  • The carbonyl stretch of an amide is typically found around 1,675 wavenumbers; while, the carbonyl stretch of an ester is typical
    14·1 answer
  • The urms of h2 molecules at 273k is 1.84×103m/s.part aat what temperature is urms for h21.8 times greater than this value?
    7·1 answer
  • When silver nitrate is added to the Fe/SCN equilibrium, why is the colorless intense and a precipitate forms?
    6·1 answer
  • What is the molar mass of Fe3(PO4)2?
    14·1 answer
  • What is an energy human eyes can detect?
    9·2 answers
  • In an exothermic reaction, chemical energy is converted to
    10·1 answer
  • How many molecules are in 2.57 moles of water ?
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!