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Advocard [28]
4 years ago
13

How many moles of bromine atoms are in 2.60 × 102 grams of bromine? 1. 0.0152 mol 2. 79.9 mol 3. 10.5 mol 4. 3.25 mol 5. 2.29 mo

l 6. 0.308 mol 7. 48.6 mol?
Chemistry
2 answers:
Lera25 [3.4K]4 years ago
8 0
Moles  =mass/ molar  mass  of  the  bromine  atom
the  molar  mass of  bromine  atom  is  79.904g/mol
mass=2.60  x10^2
therefore  the  moles  of  bromine  atom=
2.60  x10^2g/ 79.904g/mol  =3.25gmoles(answer  4)
irga5000 [103]4 years ago
5 0
<span>There are 3.25 mol of bromine atoms in 2.60 x 102 grams of bromine. I reached this answer by converting grams to moles. To do this, I divided the number of grams that I have of bromine by the weight of bromine. The weight of bromine is 80 grams. So my equation looks like this when it is all set up: 2.6 x 10^2 g/80g. The answer to the equation is 3.25 mol.</span>
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Using table 9.4, calculate an approximate enthalpy (in kj) for the reaction of 1.02 g gaseous methanol (ch3oh) in excess molecul
Tanya [424]

<u>Given:</u>

Mass of methanol = 1.02 g

<u>To determine:</u>

Enthalpy for the reaction of 1.02 g of methanol with excess O2

<u>Explanation:</u>

Balanced equation-

2CH3OH(g) + 3O2(g) → 2CO2(g) + 4H2O(g)

The reaction enthalpy is given as:

ΔHrxn = ∑nH°f(products) - ∑nH°f(reactants)

where n = number of moles

H°f = standard enthalpy of formation.

ΔHrxn = [2H°f(CO2(g)) + 4H°f(H2O(g))] - [2H°f(CH3OH(g)) + 3H°f(O2(g))]

           = [2(-393.5) + 4(-241.8)]-[2(-201.5) + 3(0)] = -1351.2 kJ

Now, 1 mole of CH3OH = 32 g

The calculated ΔHrxn corresponds to 2 moles of CH3OH. i.e.

The enthalpy change for 64 g of Ch3OH = -1351.2 kJ

Therefore, for 1.02g gaseous methanol we have:

ΔH = 1.02 * -1351.2/64 = -21.5 kJ

Ans: The enthalpy for the given reaction is -21.5 kJ



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3 years ago
Deposition is a ________________ changing into a ____________________. 1. liquid, solid 2. solid, gas 3. gas, solid 4. liquid, g
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Answer:

3. Gas, solid

Explanation:

Deposition is the process of gas changing directly to a solid. It skips the liquid state.

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The compound dioxane, which is used as a solvent in various industrial processes is composed of C,H, and O atoms. Combustion of
Lady_Fox [76]

Answer:

The correct formula of dioxane is C₄H₈O₂.

Explanation:

Given data:

mass of dioxane= 2.23 g

mass of water = 1.802 g

mass of carbon dioxide = 4.401 g

molar mass of dioxane = 88.1 g / mol

Molecular formula of dioxane = ?

Solution:

percentage of carbon = (4.401 g/2.23 g ) × (12 /44) × 100

                                     =  (1.98 × 0.273) × 100 = 54.1

percentage of hydrogen =  (1.802 g/ 2.23 g) × (2.016 /18.016) × 100

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percentage of oxygen = 100 - (54.1 + 9.072)

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Now we will determine the number of grams atoms of carbon, hydrogen and oxygen.

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No. of gram atoms of hydrogen = 9.072 / 1.008 = 9

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Atomic ratio:

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Molecular formula:

   Molecular formula = n × (empirical formula)

   n = molar mass of compound / empirical formula mass

   empirical formula mass= 2 × 12 + 4 × 1.008  + 1 × 16

    empirical formula mass= 24+ 4.032 +16 = 44.032

                 n = 88.1 / 44.032 = 2

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        Molecular formula = 2 × (C₂H₄O)

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