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Advocard [28]
4 years ago
13

How many moles of bromine atoms are in 2.60 × 102 grams of bromine? 1. 0.0152 mol 2. 79.9 mol 3. 10.5 mol 4. 3.25 mol 5. 2.29 mo

l 6. 0.308 mol 7. 48.6 mol?
Chemistry
2 answers:
Lera25 [3.4K]4 years ago
8 0
Moles  =mass/ molar  mass  of  the  bromine  atom
the  molar  mass of  bromine  atom  is  79.904g/mol
mass=2.60  x10^2
therefore  the  moles  of  bromine  atom=
2.60  x10^2g/ 79.904g/mol  =3.25gmoles(answer  4)
irga5000 [103]4 years ago
5 0
<span>There are 3.25 mol of bromine atoms in 2.60 x 102 grams of bromine. I reached this answer by converting grams to moles. To do this, I divided the number of grams that I have of bromine by the weight of bromine. The weight of bromine is 80 grams. So my equation looks like this when it is all set up: 2.6 x 10^2 g/80g. The answer to the equation is 3.25 mol.</span>
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Answer:

5.80

Explanation:

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3 years ago
The density of concentrated ammonia, which is 28.0% w/w nh3, is 0.899 g/ml. what volume of this reagent should be diluted to 1.0
vlada-n [284]

Answer: 2.4 ml

Solution :

Molar mass of NH_3 = 17 g/mole

Given,: 28% w/w of NH_3 solution means 28 g of ammonia in 100 g of solution.

Mass of solution = 100 g

Now we have to calculate the volume of solution.

Volume=\frac{Mass}{Density}=\frac{100g}{0.899g/ml}=111.2ml  

Molarity : It is defined as the number of moles of solute present in one liter of solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n = moles of solute NH_3=\frac{\text {given mass}}{\text {molar mass}}=\frac{28}{17}=1.65moles

V_s = volume of solution in liter = 0.11 L

Now put all the given values in the formula of molarity, we get

Molarity=\frac{1.65moles}{0.11L}=15mole/L

Using molarity equation:

M_1V_1=M_2V_2

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6 0
3 years ago
The main interactions between molecules of hydrogen chloride are examples of
saveliy_v [14]
Answer:
            <span>The main interactions between molecules of hydrogen chloride are examples of Dipole-Dipole Interactions.

Explanation:
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</span>

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The fuel used in many disposable lighters is liquid butane, C4H10. Butane has a molecular weight of 58.1 grams in one mole. How
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3 years ago
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Someone please help me , number 14
MrRa [10]
We know, 

PV=nRT
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3 years ago
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