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zhuklara [117]
2 years ago
6

Define Inertia.___________✨​

Physics
2 answers:
iren2701 [21]2 years ago
8 0

Answer:

a tendency to do nothing or to remain unchanged.

Explanation:

Sliva [168]2 years ago
8 0

Answer:

Inertia: The resistance an object has to a change in its state of motion.

Explanation:

Hope it helps....

Have a great day!!

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A ball rolls over the edge of a platform with only a horizontal velocity. The height of the platform is 1.60m and the horizontal
AysviL [449]

Answer:

v = 46.99 m/s

Explanation:

The velocity of the ball just before it touches the ground, is given by the following formula:

v=\sqrt{v_x^2+v_y^2}           (1)

vx: horizontal component of the velocity

vy: vertical component of the velocity

The vertical component vy is calculated by using the following formula:

v_y^2=v_{oy}^2+2gh   (2)

vy: final velocity

voy: initial vertilal velocity = 0m/s  (because it is a semi parabolic motion)

g: gravitational acceleration = 9.8 m/s^2

h: height = 1.60m

You replace the values of the parameters in the equation (2):

v_y=2(9.8m/s^2)(1.60m)=31.36\frac{m}{s}

vx is calculated by using the information about the horizontal range of the ball:

R=v_o\sqrt{\frac{2h}{g}}    (3)

R: horizontal range of the ball = 20.0 m

You solve the previous equation for vo, the initial horizontal velocity:

v_o=R\sqrt{\frac{g}{2h}}=(20.0m)\sqrt{\frac{9.8m/s^2}{2(1.60m)}}\\\\v_o=35\frac{m}{s}

The horizontal component of the velocity is constant in the complete trajectory, hence, you have that

vx = vo = 35 m/s

Finally, you replace the values of vx and vy in the equation (1):

v=\sqrt{(35m/s)^2+(31.36m/s)^2}=46.99\frac{m}{s}

The velocity of the ball just before it touches the ground is 46.99 m/s

5 0
3 years ago
I have a bottle of gas, the bottle can expand and contract. Initially the gas is at 1 kpa of pressure and a volume of 1 Liter, a
drek231 [11]

Answer:

P₂ = 1.22 kPa

Explanation:

This problem can be solved using the equation of state:

\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}

where,

P₁ = initial pressure = 1 KPa

P₂ = final pressure = ?

V₁ = initial Volume = 1 liter

V₂ = final volume = 1.1 liter

T₁ = initial temperature = 290 k

T₂ = final temperature = 390 k

Therefore,

\frac{(1\ kPa)(1\ liter)}{290\ k} =\frac{(P_2)(1.1\ liter)}{390\ k}\\\\P_2= \frac{(1\ kPa)(1\ liter)(390\ k)}{(290\ k)(1.1\ liter)}

<u>P₂ = 1.22 kPa</u>

7 0
3 years ago
a man of mass 50 kg on the top floor of skyscraper step into an elevator what is the max weight as the elevator moves downward​
shtirl [24]
514.5 N is the answer
6 0
3 years ago
You will be colliding two carts in this lab. Select all the systems for which you predict the total momentum of the system will
baherus [9]

From the momentum conservation we know that the initial momentum is equal to the final momentum. The momentum in a singular way can be defined as the product between the mass and the velocity of an object. In the presented system, however, there are two objects, therefore the mass of both and the speed of both, before and after the collision must be taken into account. Mathematically we could describe this as

m_1u_1+m_2u_2 = m_1v_1+m_2v_2

Here,

m_{1,2} = Mass of each object

u_{1,2} = Initial velocity of each object

v_{1,2} = Final velocity of each object

From here we can realize that it is necessary to use the system on both cars to be able to predict what will happen either with their masses, or their speeds.

The correct answer is C.

6 0
3 years ago
HAaaaaaaaaaaaLPPP thank you.
lara31 [8.8K]
15 guesting i think it not right
7 0
3 years ago
Read 2 more answers
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