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2 years ago

If your accelerator pedal gets stuck, what is the first thing you should do?

1 answer:

8 0

If your accelerator gets stuck down, do the following: Shift to neutral. Apply the brakes. Keep your eyes on the road and look for a way out.If your accelerator gets stuck down, do the following:

Shift to neutral.

Apply the brakes.

Keep your eyes on the road and look for a way out.

Warn other drivers by blinking and flashing your hazard lights.

Try to drive the car safely off the road.

Turn off the ignition when you no longer need to change direction.

You might be interested in

Invent five new communication method wired or wireless you think would be practical

seropon [69]

The five type of new communication method (both wire and wireless) are:

Social Media
SMS Text Messaging
Email Marketing
Direct Email
Voice Calling

<h3>What is a communication?</h3>

This means the act of giving, receiving and sharing of information as well as talking, writing, listening or reading.

The types of Communication includes:

Verbal Communication: It occurs when we engage in speaking with others.
Non-Verbal Communication: It occurs when what we speak often says more than the actual words.
Written Communication: It occurs in an actual text or writing.
Listening: It occurs when we pay attention to a speaker.

The wired communication involves transmission of data over a wire-based communication technology while a wireless communication involves transmission of data without the use of a cable or wire.

Read more about communication

brainly.com/question/26152499

#SPJ1

4 0

1 year ago

What could happen in the aviation

Alina [70]

Answer:

Yes

Explanation:

7 0

3 years ago

(20 points) A 1 mm diameter tube is connected to the bottom of a container filled with water to a height of 2 cm from the bottom

zzz [600]

Solution :

Given :

h = 2 cm

Diameter of the tube , d = 1 mm

Diameter of the hose, D = 6 mm

Between 1 and 2, by applying Bernoulli's principle, we get

As point 1 is just below the free surface of liquid, so

$P_1=P_{atm} \text{ and} \ V_1=0$

$\frac{P_{atm}}{\rho g}+\frac{v_1^2}{2g} +h = \frac{P_2}{\rho g}$

$\frac{101.325}{1000 \times 9.81}+0.02 =\frac{P_2}{\rho g}$

$P_2 = 111.35 \ kPa$

Therefore, 111.325 kPa is the gas supply pressure required to keep the water from leaking back into the tube.

Velocity at point 2,

$V_2=\sqrt{\left(\frac{111.135}{\rho g}+0.02}\right)\times 2g$

= 1.617 m/s

Flow of water, $Q_2 = A_{tube} \times V_2$

$=\frac{\pi}{4} \times (10^{-3})^2 \times 1.617$

$1.2695 \times 10^{-6} \ m^3/s$

Minimum air flow rate,

$Q_2 = Q_3 = A_{hose} \times V_3$

$V_3 = \frac{Q_2}{\frac{\pi}{4}D^2}$

$V_3 = \frac{1.2695 \times10^{-6}}{\pi\times 0.25 \times 36 \times 10^{-6}}$

= 0.0449 m/s

b). Reynolds number in hose,

$Re = \frac{\rho V_3 D}{\mu} = \frac{V_3 D}{\nu}$

υ for water at 25 degree Celsius is $8.9 \times 10^{-7} \ m^2/s$

υ for air at 25 degree Celsius is $1.562 \times 10^{-5} \ m^2/s$

$Re_{hose}=\frac{0.0449 \times 6 \times 10^{-3}}{1.562 \times 10^{-5}}$

= 17.25

Therefore the flow is laminar.

Reynolds number in the pipe

$Re = \frac{V_2 d}{\nu} = \frac{1.617 \times 10^{-3}}{8.9 \times 10^{-7}}$

= 1816.85, which is less than 2000.

So the flow is laminar inside the tube.

3 0

2 years ago

You start your car and begin to pull out of a parking space. After leaving the space, You notice that the brake light on your in

saw5 [17]

If your brake lights are staying on, it will drain your battery.The most likely cause for the brake lights staying on is the brake light switch sticking closed. You can disconnect the plug from the brake light switch at the brake light pedal to see if the lights turn off.

Hope it helped!

7 0

2 years ago

It describes the physical and social elements common to this work. Note that common contexts are listed toward the top, and less

QveST [7]

Answer:

BCDE

Explanation:

just look at the link, it tells you.

7 0

3 years ago

Read 2 more answers