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densk [106]
3 years ago
10

How does specific heat capacity affect heating rate

Chemistry
1 answer:
agasfer [191]3 years ago
3 0

Answer:

The specific heat capacity affect heating rate by the amount of heat needed to raise the temperature of 1 gram of a substance 1 degree Celsius (°C).

Explanation:

<h2>Pls mark me as brainliest</h2>
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This graph shows the titration of 25.0 ml of methylamine solution with 0.0982 m hcl. Determine the molarity of the methylamine s
sveta [45]

Answer:

0.0957 M

Explanation:

Equivalence appears to occur upon addition of 20 mls of 0.0957 M HCl.

0.02 L x 0.0957 mole/L = 0.001914 moles HCl added

CH3NH3 + HCl ==> CH3NH4^+ Cl^-

Molarity of CH3NH3 initially present = 0.0957 M

pH < 7 because the reaction is between a strong acid (HCl) and a weak base (methylamine)

7 0
3 years ago
How to keep vegetable soup from being bland?
Kipish [7]
Season it well! (: Even salt can make a ton of a difference, honestly! Just try not to add too much of anything if it's meant to be healthy and you're just trying to lose weight!
Good luck, rockstar!
4 0
3 years ago
Plsss help ASAP!!!<br> BRAINLIEST
likoan [24]

Answer:

-175.15

Explanation:

1.0 °C = 274.15 K

2.0 °C = 275.15 K

3.0 °C = 276.15 K

4.0 °C = 277.15 K

5.0 °C = 278.15 K

6.0 °C = 279.15 K

7.0 °C = 280.15 K

8.0 °C = 281.15 K

9.0 °C = 282.15 K

8 0
3 years ago
Read 2 more answers
If 50.0 g of silicon dioxide is heated with an excess of carbon, 27.9 g of silicon carbide is produced. What is the percent yiel
Molodets [167]

Answer: The percent yield of the reaction is 83.5 %

Explanation:

The given balanced equation is

SiO_2+3C\rightarrow SiC+2CO

SiO_2 is the limiting reagent as it limits the formation of product and C is the excess reagent.

According to stoichiometry :

60.08 g of SiO_2 produce = 40.11 of SiC

Thus 50.0 of SiO_2 will produce=\frac{40.11}{60.08}\times 50.0=33.4  of SiC

 Experimental yield of SiC = 27.9 g

Percent yield = \frac{\text {Experimental yield}}{\text {theoretical yield}}\times 100=\frac{27.9g}{33.4g}\times 100=83.5\%

Thus  percent yield of the reaction is 83.5 %

6 0
3 years ago
What is the change in heat energy when 114.32g of water at 14.85oC is raised to 18.00oC?
iris [78.8K]

Given:

114.32g of water

14.85oC is raised to 18.00oC

Required:

Change in heat energy

Solution:

This can be solved through the equation H = mCpT where H is the heat, m is the mass, Cp is the specific heat and T is the change in temperature.

The specific heat of the water is 4.18 J/g-K

Plugging in the values into the equation

H = mCpT

H = (114.32g) (4.18 J/g °C) (18 – 14.85)

H = 1,505.3 J

8 0
3 years ago
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