Answer:
t_total = 23.757 s
Explanation:
This is a kinematics exercise.
Let's start by calculating the distance and has to reach the limit speed of
v = 18.8 m / s
v = v₀ + a t₁
the elevator starts with zero speed
v = a t₁
t₁ = v / a
t₁ = 18.8 / 2.40
t₁ = 7.833 s
in this time he runs
y₁ = v₀ t₁ + ½ a t₁²
y₁ = ½ a t₁²
y₁ = ½ 2.40 7.833²
y₁ = 73.627 m
This is the time and distance traveled until reaching the maximum speed, which will be constant throughout the rest of the trip.
x_total = x₁ + x₂
x₂ = x_total - x₁
x₂ = 373 - 73,627
x₂ = 299.373 m
this distance travels at constant speed,
v = x₂ / t₂
t₂ = x₂ / v
t₂ = 299.373 / 18.8
t₂ = 15.92 s
therefore the total travel time is
t_total = t₁ + t₂
t_total = 7.833 + 15.92
t_total = 23.757 s
The water pressure at this depth and the total pressure due to water and atmosphere are 10.3 x 10⁵ Pa and 11.31× 10⁵ Pa.
<h3>What is pressure?</h3>
The pressure is the amount of force applied per unit area.
Atmospheric pressure, Patm =1.01×10⁵ Pa
Density of water, ρ=1030 kg/m³
Depth, h=100 m
Pressure =ρgh
P = 1030×10×100
P = 10.3 x 10⁵ Pa.
Total pressure, P=Po +ρgh
P=1.01×10⁵ + 1030×10×100
P=11.31× 10⁵ Pa
Hence, total pressure is 11.31× 10⁵ Pa.
Learn more about pressure.
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Answer:
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The Coulomb's law equation is F = Kq₁q₂/r².
<h3>
What is Coulomb's law?</h3>
This is the law that relates the product of two charges to the square of distance between the two charges.
Coulomb's law states that the force of attraction or repulsion is directly proportional to the product of the charges and inversely proportional to the square of distance between the charges.
<h3>Coulombs' law equation</h3>
The equation of Coulomb's law is given as;
F = Kq₁q₂/r²
where;
- K is Coulomb's constant, Nm²/C²
- q₁ is the first charge, C
- q₂ is the second charge, C)
- r is the distance between the charges, m
Thus, the Coulomb's law equation is F = Kq₁q₂/r².
Learn more about Coulomb's law equation here: brainly.com/question/24743340
