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saw5 [17]
2 years ago
8

Square root 12 is ___ greater than square root 7

Mathematics
1 answer:
antiseptic1488 [7]2 years ago
7 0
It’s gotta be 1.whatever
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What is the m∠q ?????????????????????? help i taking a test and imma get beat if i fail
balandron [24]

Answer:

Unlike the previous problem, this one requires application of the Law of Cosines.  You want to find angle Q when you know the lengths of all 3 sides of the triangle.

Law of Cosines:  a^2 = b^2 + c^2 - 2bc cos A

Applying that here:

                          40^2 = 32^2 + 64^2 - 2(32)(64)cos Q

Do the math.  Solve for cos Q, and then find Q in degrees and Q in radians.

Step-by-step explanation:

5 0
2 years ago
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How many decigrams are in 14 hectograms?
EleoNora [17]

Answer:

14000

Step-by-step explanation:

8 0
3 years ago
Which relationship has a zero slope?
kow [346]

The second one (straight line parallel to the y axis)

4 0
2 years ago
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Начало сказки "Снежная королева" на 20 странице, а конец на 50.
natta225 [31]

If you start on page 20 and end on Page 50, you will have read 31 pages. I just counted from 20 to 50, including the number 20 in it.

OR: You already know there are 50-20=30 pages. But that's without counting the 20 in it. So when you add the extra 20: 30 + 1 = 31

Translated version:

Если вы начнете со страницы 20 и закончите со страницы 50, вы прочтете 31 страницу. Я только что насчитал от 20 до 50, включая число 20 в нем.

ИЛИ: Вы уже знаете, что 50-20 = 30 страниц. Но это без учета 20 в нем. Поэтому, когда вы добавляете дополнительные 20: 30 + 1 = 31

Я использовал Google Translate, поэтому результаты могут быть неточными.

7 0
3 years ago
What is the rule for the following geometric sequence? 64,128,256,512...
professor190 [17]

Answer:

B

Step-by-step explanation:

The explicit rule for a geometric sequence is

a_{n} = a₁ (r)^{n-1}

where a₁ is the first term and r the common ratio

Here a₁ = 64 and r = \frac{a_{2} }{a_{1} } = \frac{128}{64} = 2 , then

a_{n} = 64 (2)^{n-1} → B

8 0
2 years ago
Read 2 more answers
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