Explanation:
The question pretty much requires us to find the amount of moles of each compounds based on the number of moles of O given.
H2SO4
1 mol of H2SO4 contains 4 mol of O
x mol of H2SO4 would contain 3.10 mol of O
x = 3.10 * 1 / 4 = 0.775 mol of H2SO4
C2H4O2
1 mol of C2H4O2 contains 2 mol of O
x mol of C2H4O2 would contain 3.10 mol of O
x = 3.10 * 1 / 2 = 1.55 mol of C2H4O2
NaOH
1 mol of NaOH contains 1 mol of O
x mol of NaOH would contain 3.10 mol of O
x = 3.10 * 1 / 1 = 3.10 mol of NaOH
D magma is another form of a volcanic eruption.
The atomic mass of a certain element is summation of the product of the decimal equivalent of the percentage abundance and the given atomic mass of each of the isotope. If we let x be the percentage abundance of the 86 amu-isotope then, the second one is 1-x such that,
x(86) + (1 - x)(90) = 87.08
The value of x from the equation is 0.73. This value is already greater than 0.5. Thus, the isotope with greatest abundance is that which is 86 amu.
Answer:
₈₄Po²²⁰
Explanation:
₈₆Rn²²⁴ → ₈₄Po²²⁰ + ₂He⁴
In given decay reaction alpha particle is emitted from Radon.
Alpha radiations:
Alpha radiations are emitted as a result of radioactive decay. The atom emit the alpha particles consist of two proton and two neutrons. Which is also called helium nuclei. When atom undergoes the alpha emission the original atom convert into the atom having mass number 4 less than and atomic number 2 less than the starting atom.
Alpha radiations can travel in a short distance.
These radiations can not penetrate into the skin or clothes.
These radiations can be harmful for the human if these are inhaled.
These radiations can be stopped by a piece of paper.
Assuming that the number of mols are constant for both conditions:
Now you plug in the given values. V_1 is the unknown.
Separate V_1
V= 162.782608696 L
There are 2 sig figs
V= 160 L