We are going to use this formula:
Q = M*C*ΔT
when Q is the heat required
M is the mass of CCl4 = 10.35 g
C is the specific heat capacity of CCl4 = 0.874J/g.c
and ΔT the change in temperature = 56.4 - 32.1 °C =24.3 °C
∴ Q = 10.35g * 0.874 * 24.3 °C
= 219.8 J
The answer was 25
Do according to bodmas rule
Answer:
30.1 g NaCl
Explanation:
Your first conversion is converting grams NaOH to moles of NaOH using its molar mass (39.997 g/mol). Then, use the mole ratio of 1 mol NaCl for every 1 mol NaOH to get to moles of NaCl. Then finally multiply by the molar mass of NaCl (58.44 g/mol) to get grams of NaCl.
20.6 g NaOH • (1 mol NaOH / 39.997 g NaOH) • (1 mol NaCl / 1 mol NaOH) • (58.44 g NaCl / 1 mol NaCl) = 30.1 g NaCl
