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mafiozo [28]
2 years ago
13

A 20 kg truck drives in a circle of radius 4 m at 10m/s. What is the

Physics
1 answer:
Tems11 [23]2 years ago
6 0
  • Mass=m=20kg
  • Radius=r=4m
  • Velocity=10m/s=v

We know

\boxed{\sf F_c=\dfrac{mv^2}{r}}

\\ \sf\longmapsto F_c=\dfrac{20(10)^2}{4}

\\ \sf\longmapsto F_c=\dfrac{20(100)}{4}

\\ \sf\longmapsto F_c=\dfrac{2000}{4}

\\ \sf\longmapsto F_c=500N

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In which material does the light wave have the larger wavelength?
pochemuha

Answer: in the smaller/ thinner pieces.

8 0
2 years ago
Pc13 is a compound used to make pesticides. A reaction requires that 96.7 kg of pc13 be raised from 31.7 degrees celcius to 69.2
siniylev [52]

Answer:

Energy required = 3169.34 Joules.

Explanation:

The quantity of energy (Q) required can be determined by;

Q = mcΔθ

Where: m is the mass, c is the specific heat and Δθ is the change in temperature.

But, m = 96.7 kg, c = 0.874 J/(kg^{o} C), T_{2} = 69.2^{o} and T_{1} = 31.7^{o}.

So that,

Q = mc(T_{2} - T_{1})

   = 96.7 x 0.874 x (69.2^{o} - 31.7^{o})

  = 96.7 x 0.874 x 37.5

  = 3169.3425

Q = 3169.34

   = 3.2 KJ

The amount of energy required is 3169.34 Joules.

8 0
3 years ago
A shopping cart given an initial velocity of 2.0 m/s undergoes a constant acceleration to a velocity of 13 m/s. What is the magn
olga55 [171]

Answer:

The acceleration is a = 2.75 [m/s^2]

Explanation:

In order to solve this problem we must use kinematics equations.

v_{f} = v_{i} + a*t\\

where:

Vf = final velocity = 13 [m/s]

Vi = initial velocity = 2 [m/s]

a = acceleration [m/s^2]

t = time = 4 [s]

Now replacing:

13 = 2 + (4*a)

(13 - 2) = 4*a

a = 2.75 [m/s^2]

5 0
3 years ago
Consider a long rod of mass, m, and length, l, which is thin enough that its width can be ignored compared to its length. The ro
ehidna [41]

Answer:

Explanation:

The rod will act as pendulum for small oscillation .

Time period of oscillation

T=2\pi\sqrt{\frac{l}{g} }

angular frequency ω = 2π / T

= \omega=\sqrt{\frac{g}{l} }

b )

ω = 20( given )

velocity = ω r = ω l

Let the maximum angular displacement in terms of degree be θ .

1/2 m v ² = mgl ( 1 - cosθ ) ,

[ l-lcosθ is loss of height . we have applied law of conservation of mechanical energy .]

.5 (  ω l )² = gl( 1 - cos θ )

.5 ω² l = g ( 1 - cosθ )

1 - cosθ  = .5 ω² l /g

cosθ = 1 - .5 ω² l /g

θ can be calculated , if value of l is given .

4 0
3 years ago
A dancer moves around a path like the one
mash [69]

Given what we know, despite not having the figure attached to the question, we can still confirm that the magnitude for the acceleration of the dancer will be zero.

<h3>Why is the dancer's acceleration equal to zero?</h3>

This has to do with how the question clarifies the speed of the dancer. Though it does not give us an exact value, we are told that the speed is constant. This is an indicator that the acceleration is zero because with any other value for acceleration the speed <u>cannot remain</u> constant.

Therefore, given that any value for acceleration will increase or decrease the speed of the dancer, but we are told that the dancer's speed is constant throughout the trip, we can confirm that the magnitude for the acceleration of the dancer is zero.

To learn more about acceleration visit;

brainly.com/question/12134554?referrer=searchResults

7 0
2 years ago
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