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densk [106]
3 years ago
5

Write any three importance of Measurement.

Physics
1 answer:
NISA [10]3 years ago
3 0

Explanation:

The three importance of measurement are as follows :-

  1. <em>measurement </em><em>is </em><em>used </em><em>to </em><em>compare</em><em> </em><em>the </em><em>items</em><em> </em><em>when </em><em>barter </em><em>system</em><em> </em><em>takes </em><em>place</em><em> </em><em>.</em>
  2. <em>measurement</em><em> </em><em>helps </em><em>in </em><em>weighing</em><em> </em><em>the </em><em>foods </em><em>,</em><em> </em><em>groceries</em><em> </em><em>etc </em><em>.</em>
  3. <em>Measurement</em><em> </em><em>are </em><em>important</em><em> </em><em>in </em><em>laboratory</em><em> </em><em>when </em><em>there </em><em> </em><em>experiments</em><em> </em><em>is </em><em>being</em><em> </em><em> </em><em>taken</em><em> </em><em> </em><em>for </em><em>different</em><em> </em><em>purposes</em><em> </em><em>.</em>

<em>Hope </em><em>it</em><em> </em><em>is </em><em>helpful</em><em> to</em><em> you</em><em> </em>

<em>✌️</em><em>✌️</em><em>✌️</em><em>✌️</em><em>✌️</em><em>✌️</em><em>✌️</em>

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What is meant by Compression and Rarefaction of a longitudinal wave?
Zepler [3.9K]
However instead of crests and troughs, longitudinal waves have compressions and rarefactions. Compression. A compression is a region in a longitudinal wave where the particles are closest together. Rarefaction. A rarefaction is a region in a longitudinal wave where the particles are furthest apart.
6 0
3 years ago
Standing waves can ruin the acoustics of a concert hall if there is excessive reflection of the sound waves that the performers
Dmitrij [34]

Answer:

The answer to the questions is;

In terms of standing waves, the listener moves from a location with high amplitude to one with lower amplitude or vibration (anti-node to node)

The distance 4.1 cm is equivalent to λ/4

Explanation:

For standing waves we have is a stationary wave comprising of two opposite direction moving waves that have equal amplitude and frequency, resulting in the superimposition of the waves. As such certain points are fixed along the wave path that is the peaks amplitude of the wave oscillation is constant at a particular point. A node occurring at a point and an anti-node occurring at another fixed point

When the listener moves 4.1 cm he or she has left the anti-node to the node hence the faintness of the sound

The distance from the node to the anti-node is 1/4 wavelength, or 1/4×λ

Therefore 4.1 cm is λ/4

6 0
3 years ago
The wheel having a mass of 100 kg and a radius of gyration about the z axis of kz=300mm, rests on the smooth horizontal plane.a.
pickupchik [31]

Answer:

a) 20 rad/s

b) 6 m/s

Explanation:

b) Force acting on the wheel is 200 N

mass of the wheel is 100 kg

From Newton's second law of motion, F = m × a

Where F is the net force acting on the body

m is mass of the body

a is the acceleration of the body

By substituting the values we get, a = 2 m/s²

As acceleration is constant, we can use the below formula for calculating the final velocity of the object

v = u + a × t

Where v is the final velocity

u is the initial velocity

a is the acceleration

t is the time taken

u = 0 (∵ it starts from rest)

By substituting the values we get

v = 0 + 2 × 3 = 6 m/s

∴ Speed of center of mass after 3 seconds = 6 m/s

a) As the wheel rotates about z-axis, radius of gyration will be the radius of wheel

∴ Radius of the wheel = 300 mm

Torque acting on the wheel about axis of rotation = 300 mm × 200 N =

60 N·m

Torque = (Moment of inertia) × (angular acceleration)

Assuming that the mass of spokes of the wheel to be negligible,

Moment of inertia of the wheel about axis of rotation = 100 × 300² × 10^{-6} = 9 kg·m²

Then,

60 = 9 × (angular acceleration)

∴ angular acceleration ≈ 6·67 rad/s²

As angular acceleration of the wheel is constant, we can use the below formula for calculation of final angular speed

w_{f} = w_{i} + α × t

Where

w_{f} is the final angular velocity

w_{i} is the initial angular velocity

α is the angular acceleration

t is the time taken

w_{i} is 0 (∵ initially it starts from rest)

By substituting the values we get

w_{f} = 6·67 × 3 = 20 rad/s

∴ Angular velocity of the wheel after three seconds = 20 rad/s

3 0
4 years ago
A Scooter travelling at 10m/s speed up to 20m/s in 4 sec.find the acceleration of scooter​
stira [4]

Answer:

2.5 m/s²

Explanation:

Given,

Initial speed ( u ) = 10 m/s

Final speed ( v ) = 20 m/s

Time ( t ) = 4 seconds

To find : Acceleration ( a ) = ?

Formula : -

a = ( v - u ) / t

a = ( 20 - 10 ) / 4

= 10 / 4

= 5 / 2

a = 2.5 m/s²

Therefore,

The acceleration of the scooter is 2.5 m/s²

7 0
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