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oee [108]
3 years ago
10

What's is meant by relative motion?​

Physics
2 answers:
MrRissso [65]3 years ago
7 0

Answer:

<em>relative</em><em> </em><em>motion </em><em>is </em><em>the </em><em>motion</em><em> </em><em>of </em><em>an </em><em>object</em><em> </em><em>compared </em><em>to </em><em>that </em><em>of </em><em>another </em><em>object.</em><em>f</em><em>o</em><em>r</em><em> </em><em>example</em><em> </em><em>two </em><em>cars </em><em>driving</em><em> </em><em>in </em><em>the </em><em>same </em><em>highway </em><em>in </em><em>the </em><em>same </em><em>direction</em><em>.</em>

<em>I </em><em>hope</em><em> this</em><em> helps</em>

saveliy_v [14]3 years ago
4 0

Relative motion means a motion relative to a reference point. We can also say, relative motion means motion referred or observed from a reference point.

For example, Alex is in a train and Ace is at the station, when the train starts moving, for Ace it is moving at a speed of 10 m/s, but for Alex it is moving at 0 m/s, or we can say that it is at rest for Alex, but in motion for Ace. This is relative motion.

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The concept required to solve this problem is hydrostatic pressure. From the theory and assuming that the density of water on that planet is equal to that of the earth (1000kg / m ^ 3)we can mathematically define the pressure as

P = \rho g h

Where,

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Rearranging the equation based on gravity

g = \frac{P_h}{\rho h}

The mathematical problem gives us values such as:

P = 2.4 atm (\frac{101325Pa}{1atm}) = 243180Pa

\rho = 1000kg/m^3

h = 28.6m

Replacing we have,

g = \frac{243180}{(1000)(28.6)}

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3 years ago
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B. Refraction

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Jope this helps

6 0
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Free_Kalibri [48]

9 × 10²¹ electrons flow through a cross section of the wire in one hour.

<h3>What is the relation between current and charge?</h3>
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  • In S.I. unit, Charge is written in Coulomb and time in second.

<h3>What is the amount of charge flown through a wire for one hour if it carries 0.4 A current?</h3>
  • Charge= current × time
  • Current= 0.4 A, time = 1 hour= 3600 s
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= 1440 C

<h3>How many numbers of electrons present in 1440C of charge?</h3>
  • One electron= 1.6 × 10^(-19) C
  • So, 1440 C = 1440/1.6 × 10^(-19)

= 9 × 10²¹ electrons

Thus, we can conclude that the 9 × 10²¹ electrons flow through a cross section of the wire in one hour.

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brainly.com/question/25922783

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The equator has no continental borders.
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