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oee [108]
3 years ago
10

What's is meant by relative motion?​

Physics
2 answers:
MrRissso [65]3 years ago
7 0

Answer:

<em>relative</em><em> </em><em>motion </em><em>is </em><em>the </em><em>motion</em><em> </em><em>of </em><em>an </em><em>object</em><em> </em><em>compared </em><em>to </em><em>that </em><em>of </em><em>another </em><em>object.</em><em>f</em><em>o</em><em>r</em><em> </em><em>example</em><em> </em><em>two </em><em>cars </em><em>driving</em><em> </em><em>in </em><em>the </em><em>same </em><em>highway </em><em>in </em><em>the </em><em>same </em><em>direction</em><em>.</em>

<em>I </em><em>hope</em><em> this</em><em> helps</em>

saveliy_v [14]3 years ago
4 0

Relative motion means a motion relative to a reference point. We can also say, relative motion means motion referred or observed from a reference point.

For example, Alex is in a train and Ace is at the station, when the train starts moving, for Ace it is moving at a speed of 10 m/s, but for Alex it is moving at 0 m/s, or we can say that it is at rest for Alex, but in motion for Ace. This is relative motion.

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disa [49]
The bending of light rays is the result of refraction of light passing through the lens. A converging lens is curved on both sides such that the rays coming out of it come together at a point (converge). The point at which the right rays meet after refraction is called the focal point which is a real in the convex lens. 
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4 years ago
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A 100g block is initially compressing a spring 5.0 cm. The spring launches the block 50cm horizontally along the ground with a f
Setler [38]

Answer:

7200 N/m

Explanation:

Metric unit conversion

100g = 0.1 kg

5 cm = 0.05 m

50 cm = 0.5 m

As the block is released from the spring and travelling to height h = 1.5m off the ground, the elastics energy is converted to work of friction force and the potential energy at 1.5 m off the ground

The work by friction force is the product of the force F = 15N itself and the distance s = 0.5 m

W_f = F_fs = 15*0.5 = 7.5 J

Let g = 10 m/s2. The change in potential energy can be calculated as the following:

E_p = mgh = 0.1*10*1.5 = 1.5 J

Therefore, as elastic energy is converted to potential energy and work of friction:

E_e = W_f + E_p

kx^2/2 = 7.5 + 1.5 = 9 J

k = 9*2/x^2 = 18/0.05^2 = 7200 N/m

6 0
3 years ago
A car traveling at 23m/s starts to decelerate steadily. It comes to a complete stop in 7 seconds. What is the acceleration?
Lena [83]

The car has an initial velocity v_0 of 23 m/s and a final velocity v of 0 m/s. Recall that for constant acceleration,

v=v_0+at

The car stops in 7 s, so the acceleration is

0\,\dfrac{\mathrm m}{\mathrm s}=23\,\dfrac{\mathrm m}{\mathrm s}+a(7\,\mathrm s)

\implies a\approx-3.29\,\dfrac{\mathrm m}{\mathrm s^2}

7 0
3 years ago
A car starting from rest has a constant acceleration of 4 meters per second per second. How fast will it be going in 5 seconds?
irinina [24]

Answer:

18 m

Explanation:

Given : vo = 0 m/s ; t = 3 s; a = 4 m/s^2 ; d = ? m ; average velocity = ? m/s ; fonal velocity = ? m/s

solving for the final velocity, v

v = a * t

v = 4 m/s^2 * 3 s

v = 12 m / s

Solving for the average velocity. avg v

avg v = (vo + v) / 2

avg v = (0 m / s + 12 m/s) / 2

avg v = 6 m / s

Solving for the distance traveled after 3 s

d = avg v * t

d = 6 m / s * 3 s

d = 18 meters

In the first 3s the car travels 18 meters.

4 0
3 years ago
If R is the total resistance for a parallel circuit with two resistors of resistance r1 and r2, then . Find the resistance, r1,
Goshia [24]
For a parallel circuit with two resistors, the total resistance is calculated from the expression:

1/R = 1/R1 + 1/R2

We are given the total resistance, R, which is 20 ohms and R2 which is 75 ohms. We calculate R1 as follows:

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3 years ago
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