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oee [108]
3 years ago
10

What's is meant by relative motion?​

Physics
2 answers:
MrRissso [65]3 years ago
7 0

Answer:

<em>relative</em><em> </em><em>motion </em><em>is </em><em>the </em><em>motion</em><em> </em><em>of </em><em>an </em><em>object</em><em> </em><em>compared </em><em>to </em><em>that </em><em>of </em><em>another </em><em>object.</em><em>f</em><em>o</em><em>r</em><em> </em><em>example</em><em> </em><em>two </em><em>cars </em><em>driving</em><em> </em><em>in </em><em>the </em><em>same </em><em>highway </em><em>in </em><em>the </em><em>same </em><em>direction</em><em>.</em>

<em>I </em><em>hope</em><em> this</em><em> helps</em>

saveliy_v [14]3 years ago
4 0

Relative motion means a motion relative to a reference point. We can also say, relative motion means motion referred or observed from a reference point.

For example, Alex is in a train and Ace is at the station, when the train starts moving, for Ace it is moving at a speed of 10 m/s, but for Alex it is moving at 0 m/s, or we can say that it is at rest for Alex, but in motion for Ace. This is relative motion.

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An investigation has been completed similar to the one on latent heat of fusion, where steam is bubbled through a container of w
allochka39001 [22]

Answer:

Q_a=330 cal

Q_w=6000cal

Explanation:

From the question we are told that

Mass of the aluminum container 50 g

Mass of the container and water 250 g

Mass of the water 200 g

Initial temperature of the container and water 20°C

Temperature of the steam 100°C

Final temperature of the container, water, and condensed steam 50°C

Mass of the container, water, and condensed steam 261 g

Mass of the steam 11 g Specific heat of aluminum 0.22 cal/g°C

a) Heat energy on container

Generally the formula for mathematically solving heat gain

      Q_c=M_c *C_c*( \triangle T)

Therefore imputing variables we have

      Q_a=50g *0.22*50-20  

      Q_a=330 cal

b) Heat energy on water

Generally the formula for mathematically solving heat gain

       Q_w=M_w *C_w*( \triangle T)

Therefore imputing variables we have

       Q_w=200 *1* 50-204

       Q_w=6000cal

7 0
3 years ago
A 78.5-kg man is standing on a frictionless ice surface when he throws a 2.40-kg book horizontally at a speed of 11.3 m/s. With
kirill [66]

Answer:

The man moves across the ice with a speed of 0.345m/s.

Explanation:

From the conservation of linear momentum, we have that the total linear momentum before the book throw is equal to the total linear momentum just after it. Since the initial velocity of the system is zero (so the initial momentum is zero), we have that:

m_mv_m+m_bv_b=0\\\\v_m=-\frac{m_b}{m_m} v_b

Where m_m is the mass of the man, m_b is the mass of the book, and v_m and v_b are their velocities. Plugging in the given values, we can compute the speed of the man (ignoring the negative sign, because we care about the magnitude, not the direction):

v_m=\frac{2.40kg}{78.5kg}(11.3m/s)=0.345m/s

In words, the resulting speed of the man is 0.345m/s.

8 0
3 years ago
Read 2 more answers
What piece of sports equipment is aerodynamic
Mashcka [7]
Aerobie.  Frisbee.  Discus.  Javelin.  I suppose an American football to some extent. 
<span>Pull!  Clay pigeons.  Arrows.  Wingsuit.  Kites.  Hang gliders.  Sails.  sailboat keels/dagger boards.  Water skis.  Ski jumping skis.  Boomerang.  </span>
<span>I'm excluding spheres and parachutes as bluff bodies even though aerodynamics often plays a big part in their motion.</span>
6 0
3 years ago
A lamp draws a current of 0.50 A when it is connected to a 120 V source? What is the resistance of the lamp?
emmainna [20.7K]
Given,
Current (I) = 0.50A
Voltage (V) = 120 volts
Resistance (R) =?
We know that:-
Voltage (V) = Current (I) x Resistance (R)
→Resistance (R) = Voltage (V) / Current (I)
= 120/0.50
= 24Ω
∴ Resistance (R) = 24Ω
8 0
3 years ago
Read 2 more answers
Is this right at all
Alja [10]
It is correct! good job :)
7 0
3 years ago
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