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marin [14]
3 years ago
11

Work out

Physics
1 answer:
Simora [160]3 years ago
6 0

the father has to sit 0.5meter away from the kid because he is a 3/4 heavier that the kid

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How does heat transfer? (Think temperature)​
yulyashka [42]

Answer:

The rate at which temperature changes is proportional to the rate at which heat is transferred.

Explanation:

The temperature of a sample changes more rapidly if heat is transferred at a high rate and less rapidly if heat is transferred at a low rate

5 0
3 years ago
Review. For a certain type of steel, stress is always proportional to strain with Young's modulus 20 × 10¹⁰ N/m² . The steel has
Nostrana [21]

The strain in the rod is 2.37\times 10^{-3}

Given:

Young's modulus, Y = 20 \times 10^{10}\;N/m^{2}

Steel density, \rho = 7.86 \times 10^{3}\;kg/m^{3}

Length of the rod, L = 80 cm = 0.800m

The speed of the wave in the rod is,

$v = \sqrt{\frac{Y}{\rho}} = \sqrt{\frac{20\times 10^{10}\ \mathrm{N/m^2}}{7.86\times 10^3\ \mathrm{kg/m^3}}} = 5044\ \mathrm{m/s}$

Hence the time taken by the wave to travel the end of the rod is,

$t=\frac{L}{v} = \frac{0.800\ \mathrm{m}}{5044\ \mathrm{m/s}} = 1.58\times 10^{-4}\ \mathrm{s}$

The velocity of the rod is, $v_r = 12.0\ \mathrm{m/s}$

The other end will keep moving after the front end hits the wall until the wave reaches the other end, given the period determined by the above problem.

As a result, before the wave reaches the end of the rod, it has traveled a distance of

$\Delta L = v_r t = (12.0\ \mathrm{m/s}) (1.58\times\ \mathrm{s}) = 1.90\times 10^{-3}\ \mathrm{m} = 1.90\ \mathrm{mm}$

The strain in the rod is given by,

$\frac{\Delta L}{L} = \frac{1.90\times 10^{-3}\ \mathrm{m}}{0.800\ \mathrm{m}} = 2.37\times 10^{-3}

Hence, the strain in the rod is 2.37\times 10^{-3}.

<h3>What is strain?</h3>

In terms of physics, strain is defined as the fractional modification of configuration.

A system's reaction to an applied stress is called a strain, according to 2. A force that loads a material results in a stress that leads to deformation. Formula for a strain

Change in configuration equals strain first arrangement

It is a dimensionless quantity that lacks a unit.

Change in object size / original object size is known as strain.

It is a quantity without units or dimensions.

Strain kind.

Object length change divided by starting object length equals longitudinal strain.

L/L stands for longitudinal strain.

Change in object volume divided by starting object volume equals longitudinal strain

To know more about Strain visit:

brainly.com/question/19317733

#SPJ4

7 0
2 years ago
4. For a point charge, we derived an expression from Gauss’s law for the electric field a distance r away. You have a point char
IrinaVladis [17]

Answer:

Explanation:

A point charge of +2q centered in a conductive spherical shell of inner diameter a and outer diameter b will induce - 2q charge on the inner surface and +2q charge on the outer surface of the shell. Since 8q charge has been added to the shell , this charge will reside on the outer surface of the shell. so total charge on the outer surface will be 10q.  At a point less than a , the electric field will be due to +2q charge situated at the centre . The electric field will be as follows

E = k .2q / r² for r < a

= 8kq/ a²

electric field at a point  r = a>b

total charge  lying inside is +2q - 2q = 0 . So in the thickness of the shell , electric field will be zero as total charge inside is nil.

For a point at r > b total charge inside is 2q-2q+10q = 10q , so electric field at r which is lying outside  the shell .

E = k 10 q / r² for r > b

8 0
4 years ago
What is the resistance of : A) A 1.70 m long copper wire that is 0.700 mm in diameter? B) A 20.0 cm long piece of carbon with a
astra-53 [7]

Answer:

(I). The resistance of the copper wire is 0.0742 Ω.

(II). The resistance of the carbon piece is 1.75 Ω.

Explanation:

Given that,

Length of copper wire = 1.70 m

Diameter = 0.700 mm

Length of carbon piece = 20.0 cm

Cross section areaA = (2.00\times10^{-3})^2\ m

(I). We need to calculate the area of copper wire

Using formula of area

A=\pi r^2

A=3.14\times(\dfrac{0.700\times10^{-3}}{2})^2

We need to calculate the resistance

Using formula of resistance

R=\dfrac{\rho l}{A}

Put the value into the formula

R=\dfrac{1.68\times10^{-8}\times1.70}{3.14\times(\dfrac{0.700\times10^{-3}}{2})^2}

R=0.0742\ \Omega

(II). We need to calculate the resistance

Using formula of resistance

R=\dfrac{\rho l}{A}

Put the value into the formula

R=\dfrac{3.5\times10^{-5}\times20\times10^{-2}}{(2.00\times10^{-3})^2}

R=1.75\ \Omega

Hence, (I). The resistance of the copper wire is 0.0742 Ω.

(II). The resistance of the carbon piece is 1.75 Ω.

8 0
4 years ago
what is the force of static friction on Earth between a 2000 kg car and the road if a coefficient of static friction is 0.4?​
Nana76 [90]

Answer:

7840 N

Explanation:

F = Nμ

F = mgμ

F = (2000 kg) (9.8 m/s²) (0.4)

F = 7840 N

6 0
3 years ago
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