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Gre4nikov [31]
3 years ago
15

In a very busy off-campus eatery one chef sends a 235-g broccoli-tomato-pickle-onion-mushroom pizza sliding down the counter fro

m left to right at 1.65 m/s. Almost simultaneously, the other chef launches a 351-g veggieburger-on-a-bun (with everything, but hold the horseradish) along the same counter from right to left at 2.47 m/s. The two delicacies collide head on at the given speeds–the counter is practically friction-free due to accumulated grease–and merge into a single, unbelievably savory serving. In what direction does the delectible dish move, if it moves at all?
Physics
1 answer:
STALIN [3.7K]3 years ago
3 0

Answer:

0.47922 kgm/s and will move right to left

Explanation:

m_1 = Mass of broccoli-tomato-pickle-onion-mushroom pizza = 235 g

m_2 = Mass of veggieburger-on-a-bun = 351 g

v_1 = Velocity of broccoli-tomato-pickle-onion-mushroom pizza = 1.65 m/s

v_2 = Velocty of veggieburger-on-a-bun = -2.47 m/s

Left to right is considered positive direction and the opposite is negative direction

Net momentum is

p=m_1v_1+m_2v_2\\\Rightarrow p=0.235\times 1.65+0.351\times -2.47\\\Rightarrow p=-0.47922\ kgm/s

The combined dish has a momentum of 0.47922 kgm/s and will move right to left

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3 years ago
1. When you have different masses for each sphere, how does the force that the larger mass sphere exerts on the smaller mass sph
aleksandrvk [35]

1) The forces are equal (Newton's third law of motion)

2) The force between the spheres will quadruple

3) The force of gravity exerted by the notebook on you is negligible

Explanation:

1)

In this part of the problem, we want to compare the gravitational force exerted by the larger mass sphere on the smaller mass sphere to the force exerted by the smaller mass sphere to the larger mass sphere.

We can do this by using Newton's third law of motion, which states that:

<em>"When an object A exerts a force (called </em><em>action</em><em>) on an object B, then object B exerts an equal and opposite force (called </em><em>reaction</em><em>) on object A"</em>

In this problem, we can identify the larger mass sphere as object A and the smaller mass sphere as object B. This law tells us that the two forces are equal in magnitude and opposite in direction: therefore, the gravitational force exerted by the larger mass sphere on the smaller mass sphere is equal to the force exerted by the smaller mass sphere to the larger mass sphere.

2)

The magnitude of the gravitational force between the two spheres is given by

F=G\frac{m_1 m_2}{r^2}

where

G is the gravitational constant

m_1, m_2 are the masses of the two spheres

r is the separation between the two spheres

In this problem, we are asked to find what happens when the distance between the spheres is halved, therefore when the new distance is

r'=\frac{r}{2}

Substituting into the equation, we find

F'=G\frac{m_1 m_2}{r'^2}=G\frac{m_1 m_2}{(r/2)^2}=4(\frac{Gm_1 m_2}{r^2})=4F

So, the force between the two spheres will quadruple.

3)

We can give an estimate for the gravitational force exerted by your notebook on you.

As we said, the magnitude of the gravitational force is

F=G\frac{m_1 m_2}{r^2}

Where:

G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2} is the gravitational constant

Let's estimate the following:

m_1 = 60 kg is your mass

m_2 = 2 kg is the mass of the notebook

r=1 m, assuming the notebook is at 1 metre from you

Substituting,

F=(6.67\cdot 10^{-11})\frac{(60)(2)}{1^2}=8.0\cdot 10^{-9} N

We see that this force has an extremely small value: therefore, it is almost negligible in daily life, where other much stronger forces act on you.

Learn more about gravity:

brainly.com/question/1724648

brainly.com/question/12785992

#LearnwithBrainly

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Answer:

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Answer:

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