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Gre4nikov [31]
3 years ago
15

In a very busy off-campus eatery one chef sends a 235-g broccoli-tomato-pickle-onion-mushroom pizza sliding down the counter fro

m left to right at 1.65 m/s. Almost simultaneously, the other chef launches a 351-g veggieburger-on-a-bun (with everything, but hold the horseradish) along the same counter from right to left at 2.47 m/s. The two delicacies collide head on at the given speeds–the counter is practically friction-free due to accumulated grease–and merge into a single, unbelievably savory serving. In what direction does the delectible dish move, if it moves at all?
Physics
1 answer:
STALIN [3.7K]3 years ago
3 0

Answer:

0.47922 kgm/s and will move right to left

Explanation:

m_1 = Mass of broccoli-tomato-pickle-onion-mushroom pizza = 235 g

m_2 = Mass of veggieburger-on-a-bun = 351 g

v_1 = Velocity of broccoli-tomato-pickle-onion-mushroom pizza = 1.65 m/s

v_2 = Velocty of veggieburger-on-a-bun = -2.47 m/s

Left to right is considered positive direction and the opposite is negative direction

Net momentum is

p=m_1v_1+m_2v_2\\\Rightarrow p=0.235\times 1.65+0.351\times -2.47\\\Rightarrow p=-0.47922\ kgm/s

The combined dish has a momentum of 0.47922 kgm/s and will move right to left

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Answer:

1600 \frac{m}{s^2}

Explanation:

Acceleration is defined as the change in velocity divided by the time it took to produce such change. The formula then reads:

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Therefore we have:

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