Answer:
a. Moles of 
= 0.001643 moles
b. 0.296 g
c. 0.3098 g
d. Not acceptable
Explanation:
a.
Considering:
Or,
Given :
For :
Molarity = 0.1052 M
Volume = 15.62 mL
The conversion of mL to L is shown below:
1 mL = 10⁻³ L
Thus, volume = 15.62×10⁻³ L
Thus, moles of :
Moles of = 0.001643 moles
b.
The reaction of NaOH with the acetylsalicylic acid is in the ratio of 1:1.
Thus, Moles of NaOH = Moles of acetylsalicylic acid = 0.001643 moles
Molar mass of acetylsalicylic acid = 180.16 g/mol
The formula for the calculation of moles is shown below:
Thus,
Mass = Moles * Molar mass = 0.001643 moles * 180.16 g/mol = 0.296 g
c.
1.159 g of sample contains 0.296 g of acetylsalicylic acid
1.213 g of sample contains 
g of acetylsalicylic acid
Mass of acetylsalicylic acid = 0.3098 g = 309.8 mg
d. Sample contains = 309.8 mg
Manufacturer claiming = 315 mg to 335 mg
Thus , it is not acceptable.
Answer:
Polar covalent bond.
Explanation:
When the bond is formed between the atoms by sharing the electrons the bond thus have covalent character. The atom with larger electronegativity attract the electron pair more towards it self and becomes partial negative while the other atom becomes partial positive. When the electronegativity difference is less than 0.4 the bond is non polar covalent.
When bonded atoms have greater electronegativity difference i.e 2 or greater than two the bond is ionic because electron is transfer from low electronegative atom to highest electronegative atom.
For example:
In water the electronegativity of oxygen is 3.44 and hydrogen is 2.2. That's why electron pair attracted more towards oxygen, thus oxygen becomes partial negative and hydrogen becomes partial positive.
In case of H₂, Cl₂, Br₂ the bond has very high covalent character because of zero electronegativity difference.
Albinism is a recessive trait.
Answer:
0.1035 M
Explanation:
Considering:
Sodium chloride will furnish Sodium ions as:
Given :
For Sodium chloride :
Molarity = 0.288 M
Volume = 3.58 mL
The conversion of mL to L is shown below:
1 mL = 10⁻³ L
Thus, volume = 3.58×10⁻³ L
Thus, moles of Sodium furnished by Sodium chloride is same the moles of Sodium chloride as shown below:
Moles of sodium ions by sodium chloride = 0.00103104 moles
Sodium sulfate will furnish Sodium ions as:
Given :
For Sodium sulfate :
Molarity = 0.001 M
Volume = 6.51 mL
The conversion of mL to L is shown below:
1 mL = 10⁻³ L
Thus, volume = 6.51 ×10⁻³ L
Thus, moles of Sodium furnished by Sodium sulfate is twice the moles of Sodium sulfate as shown below:
Moles of sodium ions by Sodium sulfate = 0.00001302 moles
Total moles = 0.00103104 moles + 0.00001302 moles = 0.00104406 moles
Total volume = 3.58 ×10⁻³ L + 6.51 ×10⁻³ L = 10.09 ×10⁻³ L
Concentration of sodium ions is:
<u>
The final concentration of sodium anion = 0.1035 M</u>
