Answer:
Explanation:
We can use Newton's Second Law to solve this exercise, which states that an object of mass m subjected by a force of magnitude F will experiment an acceleration given by the formula F=ma. I our case we want the acceleration, so we can write a=F/m, and use the values given:
a=F/m=(1000N)/(1000kg)=1m/s2.
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Answer:
8.25 x 10^-3 V/m
Explanation:
Resistivity, ρ = 2.44 x 10^-8 Ohm m, Diameter = 1.8 mm
radius, r = 0.9 mm = 0.9 x 10^-3 m, l = 40 cm = 0.4 m, i = 860 mA = 0.86 A,
Let V be the potential difference and E be the electric field.
Use the formula for resistance
R = ρ l / A
R = (2.44 x 10^-8 x 0.4) / ( 3.14 x 0.9 x 0.9 x 10^-6)
R = 3.84 x 10^-3 ohm
According to Ohm's law
V = i x R
V = 0.860 x 3.84 x 10^-3 Volt = 3.3 x 10^-3 Volt
E = V / l = 3.3 x 10^-3 / 0.4 = 8.25 x 10^-3 V/m
When they bounce off a barrier
Explanation:
Antinodes are not the same thing as the amplitude , but they are very closely related. The amplitude is the distance from the rest position of the wave to the antinode . The antinode is just a point along the wave that has the greatest maximum velocity in the y-direction.
The amplitude of a standing wave doesn't remain the same throughout the wave. It keeps on changing as it is a function of x.
Where the amplitude is minimum is called?
The locations at which the absolute value of the amplitude is minimum are called nodes, and the locations where the absolute value of the amplitude is maximum are called antinodes.