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3 years ago

How does mercury differ from other metals?(1 point)

Physics

2 answers:

faltersainse [42]3 years ago

5 0

Answer:

It is not solid under normal conditions

IrinaK [193]3 years ago

4 0

Mercury is liquid at room temperature

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On the position vs time graph a curved line represents ____________.

Art [367]

The velocity is changing.

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3 years ago

What happens to the diffraction pattern when the number of lines per centimeter of a diffraction grating is increased?

timofeeve [1]

The separation between two neighboring vital maxima increments. As the quantity lines per centimeter expand, the detachment d between neighboring openings ends up noticeably littler. The point that determines primary maxima of a diffraction grinding is given by transgression = m/d, where is the wavelength and m = 0, 1, 2, 3. For settled estimations of m and the wavelength, this connection demonstrates that as d abatements, increments. For a settled screen area, this implies the separation between two neighboring chief maxima additionally increments.

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3 years ago

ou are walking down a straight path in a park and notice there is another person walking some distance ahead of you. The distanc

alexgriva [62]

Answer:

The value is $d = 31.45 \ m$

Explanation:

Generally the relative speed at which you are moving with respect to the person ahead of you is mathematically represented as

$v_r = v_s - v_c$

substituting 1.05 m/s for $v_c$ and 2.75 m/s for $v_s$

$v_r = 2.75 - 1.05$

=> $v_r = 1.7 \ m/s$

Generally the distance by which the person is ahead of you is mathematically represented as

$d = v_r * t$

substituting 18.5 s for $t$

$d = 1.7 * 18.5$

=> $d = 31.45 \ m$

4 0

3 years ago

A 87 kgkg skydiver can be modeled as a rectangular "box" with dimensions 18 cmcm ×× 47 cmcm ×× 180 cmcm . If he falls feet first

garik1379 [7]

Answer:

Therefore the terminal velocity = 1.45 m/s

Explanation:

Terminal velocity: Terminal velocity is the highest velocity of an object when it falls from rest trough a media.

$V_t=\sqrt{\frac{2w}{c_d\rho A}}$

$V_t$ = terminal velocity

w = weight of the object = mg

$c_d$ = drag coefficient=0.80

A= frontal area

$\rho$ = media density = 1.2 kg/m³

m = mass = 8 kg

g= acceleration due to gravity = 9.8 m/s²

Front area = length× breadth

= (18×47)cm²

=846 cm²

Therefore the terminal velocity

$v_t= \sqrt{\frac{2\times 87\times 9.8}{0.80\times 846 \times 1.2}$

=1.45 m/s

Therefore the terminal velocity = 1.45 m/s

8 0

4 years ago

Doubling an object’s height will have what effect on its potential energy due to gravity?

timurjin [86]

Potential energy due to gravity = Ep = mgh [symbols have their usual meaning ]
Evidently, HALVING the mass will make Ep , HALF its previous value. So, It will be halved.

5 0

3 years ago

Read 2 more answers