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sukhopar [10]
3 years ago
15

One charge is fixed q1 = 5 µC at the origin in a coordinate system, a second charge q2 = -3.2 µC the other is at a distance of x

= 90 m from the origin.
What is the potential energy of this pair of charges?
Physics
1 answer:
mel-nik [20]3 years ago
5 0

Answer:

5.4uC

Explanation:

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What happens in terms of energy when a moving car hits a parked car, causing the parked car to move?
meriva
This is an example Newton's Third Law. All the kinectic energy from the moving car transferred the potential energy of the parked car. This potential is not much since the brakes are on (hopefully) and it's not in a non-moving position.
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a crate is lifted vertically 1.5 m and then held at rest. the crate has weight 100 n (i.e., it is supported by an upward force o
san4es73 [151]

The required work to hold the crate above the ground is 150 joule.

We need to know about the work done to solve this problem. The work done by an object depends on the force applied and the distance. The work is proportional to force and displacement. It can be written as

W = F . s

where W is work done, F is the force and s is displacement

From the question above, the given parameters are

F = 100 N

s = 1.5

Thus, the required work to hold the crate above the ground can be calculated

W = F . s

W = 100 . 1.5

W = 150 joule

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6 0
1 year ago
A boy of mass 50 kg walks up a staircase of 10 steps each 15 cm high. Calculate the work done.​
Burka [1]

Answer:

735 J

Explanation:

Total height reached(displaced)=10x15 cm

= 10 x 15/100 m

= 1.5 m

Workdone = F.S (force x displacement)

Here, the boy is traveling against the gravitation force(=mg) , and traveled a height of 1.5m

Hence,

Workdone = 50 x 9.8 x 1.5 J

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3 0
3 years ago
7 kilogram object collides with a stationary 3 kg object and after collision they stick together and move forward with velocity
stira [4]

Answer:

Explanation: velocity 4m/s is found by: 7-3 so if you want to find Velocity for 10kg You need to do 10-3

The answer is 7m/s

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4 0
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A secant and a tangent meet at a 90° angle outside the circle. What must be the difference between the measures of the interc
kozerog [31]

The difference between the measures of the intercepted arcs of the given circle is 45°.

A circle is defined as the set of points in a plane equidistant to each, such that it forms a closed two-dimensional figure, which is known as a circle.

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  • The intercepted arc is the section of the circumference of a circle such that it is either encased by two chords or a line segment, meeting at a single point.

We are given that the angle subtended by secant and tangent, outside the circle is,

\theta =90^{\circ}

And angle measured inside the circle is,

\phi = \theta /2\\\\\phi = 90/2\\\\\phi = 45{^\circ}

So, the difference between the measures of the intercepted arcs is,

\theta' = \theta - \phi\\\\\theta' = 90-45\\\\\theta' =45^{\circ}

Thus, we can conclude that the difference between the measures of the intercepted arcs of the given circle is 45°.

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4 0
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