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sukhopar [10]
2 years ago
15

One charge is fixed q1 = 5 µC at the origin in a coordinate system, a second charge q2 = -3.2 µC the other is at a distance of x

= 90 m from the origin.
What is the potential energy of this pair of charges?
Physics
1 answer:
mel-nik [20]2 years ago
5 0

Answer:

5.4uC

Explanation:

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It has no units. not sure.
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A pontoon boat travels across a lake in a straight line and increases in speed uniformly from vi = 18.5 m/s to vf = 36.0 m/s in
omeli [17]

Answer:

Explanation:

a ) The motion is one dimensional , so motion is along x - axis , starting from origin ( 0 , 0 )

b ) Initial velocity is 18.5 m /s when boat is situated at origin . When he displaces by 250 m along x axis and his position is ( 250 , 0 ) along x axis , his velocity becomes 36 m /s . Both his velocity and acceleration is along x - axis.

c ) Initial velocity vi = 18.5 m /s

final velocity vf = 36 m/s

Displacement x  = 250 m

Acceleration a = ?

Most appropriate formula is given below .

vf² = vi² + 2 a x

2ax = vf² - vi²

x =  ( vf² - vi² ) / 2 a

d )

Putting the given values

36² - 18.5² / 2 x 250

= 1296 - 342.25 / 500

= 1.9 m /s².

f ) Time interval t = ?

Required formula

vf = vi + at

t = (vf - vi ) / a

Putting the values

t = (30 - 18.5) / 1.9

= 6.05 second .

8 0
2 years ago
Meg goes swimming on a hot afternoon. When she comes out of the pool, her foot senses that the pavement is unbearably hot. Suppo
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If 27 J of work are needed to stretch a spring from 15 cm to 21 cm and 45 J are needed to stretch it from 21 cm to 27 cm, what i
kupik [55]

Answer:

9 cm.

Explanation:

The energy used for stretch the spring from 15 cm to 21 cm will be , E_{1}=27J

The energy used for stretch the spring from 21 cm to 27 cm will be , E_{2}=45J

using the energy of spring formula ,we find that

27 = \frac{1}{2}K((21-L^{2})-(15-L^{2}))

45 = \frac{1}{2}K((27-L^{2})-(21-L^{2}))

Dividing both the equation will get,

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Therefore, the natural length of the spring is, 9 cm.

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3 years ago
A basketball is tossed upwards with a speed of 5.0 m/s. We can ignore air resistance. What is the maximum height reached by the
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Answer:

the maximum height is 1.276 meters

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