Answer:
atomic mass of X is 48.0 amu
Explanation:
Let y be the atomic mass of X
Molar mass of O_2 is = 2×16 = 32 g / mol
X + O2 -----> XO_2
According to the equation ,
y g of X reacts with 32 g of O_2
24 g of X reacts with Z g of O_2
Z = ( 32×24) / y
But given that 24.0 g of X exactly reacts with 16.0 g of O_2
So Z = 16.0
⇒ (32×24) / y = 16.0
⇒ y = (32×24) / 16
y= 48.0
So atomic mass of X is 48.0 amu
Answer:
The answer to your question is Final volume = 58.37 ml
Explanation:
Data
density = 8.96 g/cm³
mass = 75 g
volume of water = 50 ml
Process
1.- Calculate the volume of copper
Density = mass / volume
Solve for volume
Volume = mass / density
Substitution
Volume = 75/8.96
Simplification
Volume = 8.37cm³ or 8.37 cm³
2.- Calculate the new volume of water in the graduated cylinder
Final volume = 50 + 8.37
Final volume = 58.37 ml
Answer:
See below
Explanation:
.75 = 1/2^(40/h)
log .75 / ( log 1/2) = 40 / h
<u>h = half life = 96.37683 min</u>
0.347 mols, working out shown on photo
